with what?..................
They are the same easily answer metals all the way
We know that there is 1 mole of Mn for every 1 mole of
KMnO4, therefore the molarity of Mn is similar with KMnO4:
Mn = 0.00300 M
Molar mass of Mn is 54.94 g / mol. Molarity (M) is moles /
L, therefore:
Mn = (0.00300 moles / L) * (54.94 g / mol) * (1000 mg / g)
<span>Mn = 164.82 mg / L = 164.82 ppm</span>
Answer is: <span>requirement of valine is 0,0222 mol for a100 kilograms adult.
</span>m(C₅H₁₁NO₂) = 2,60 g.
M(C₅H₁₁NO₂) = 5 · 12 + 11 · 1 + 1 · 14 + 2 · 16 · g/mol.
M(C₅H₁₁NO₂) = 117 g/mol.
n(C₅H₁₁NO₂) = m(C₅H₁₁NO₂) ÷ M(C₅H₁₁NO₂).
n(C₅H₁₁NO₂) = 2,60 g ÷ 117 g/mol.
n(C₅H₁₁NO₂) = 0,0222 mol.
n - amount of substance.
m - mass of substance.
M - molar mass of substance.