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Damm [24]
3 years ago
16

A road is made in such a way that the center of the road is higher off the ground than the sides of the road, in order to allow

rainwater to drain. A cross-section of the road can be represented on a graph using the function f(x) = -1/200(x – 16)(x + 16), where x represents the distance from the center of the road, in feet. Rounded to the nearest tenth, what is the maximum height of the road, in feet?

Mathematics
2 answers:
svetoff [14.1K]3 years ago
9 0

Answer:

These are the answers you can choose in edgunity.

A. 0.1

B. 0.8

C. 1.3

D. 1.6

unfortunately I do not know the answer to the question though...

I think it might be C. though.

Jet001 [13]3 years ago
4 0

Remark.

The problem is a bit indistinct. Where exactly are the two edges of the road? I'm going to say that they are the x intercepts, but that may not be true. Certainly it does not have to be true at all.


Graph.

A graph has been made for you. The maximum is marked for you. It is an approximation The actual height can be more accurately found.


Height

y = (-1/200)(x - 16)(x + 16)

y = (-1/200)*(x^2 - 256)


The maximum height for this graph only is when x = 0.Other graphs require completing the square.


y = (-1/200) * (-256)

y = 1.28 exactly. I thought the graph might be rounding the answer. It is not.

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Using the binomial distribution, it is found that there is a 0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For each die, there are only two possible outcomes, either a 3 or a 4 is rolled, or it is not. The result of a roll is independent of any other roll, hence, the <em>binomial distribution</em> is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

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  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • There are 9 rolls, hence n = 9.
  • Of the six sides, 2 are 3 or 4, hence p = \frac{2}{6} = 0.3333

The desired probability is:

P(X \geq 2) = 1 - P(X < 2)

In which:

P(X < 2) = P(X = 0) + P(X = 1)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{9,0}.(0.3333)^{0}.(0.6667)^{9} = 0.026

P(X = 1) = C_{9,1}.(0.3333)^{1}.(0.6667)^{8} = 0.117

Then:

P(X < 2) = P(X = 0) + P(X = 1) = 0.026 + 0.117 = 0.143

P(X \geq 2) = 1 - P(X < 2) = 1 - 0.143 = 0.857

0.857 = 85.7% probability that at least 2 of the rolls come up as a 3 or a 4.

For more on the binomial distribution, you can check brainly.com/question/24863377

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