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Alja [10]
4 years ago
8

Pls help me. I will mark you as brainly if you help me get the correct answer.

Mathematics
2 answers:
kakasveta [241]4 years ago
7 0

Answer:

D

Step-by-step explanation:

9x+(5y+x)-3y

Remove the parenthesis

When there is a "+" in front of an expression in parentheses, the expression remains the same

9x+5y+x-3y

Collect like terms

(9x+x)+(5y-3y)

10x+2y

MatroZZZ [7]4 years ago
5 0

Answer:

C and D

Step-by-step explanation:

Let's add this all together.

9x + 5y + x - 3y

Combine like terms 5y + -3y and 9x + x

10x + 2y

So we know D is at least correct.

What else? C is also correct, because we can expand it outward.

10x + 5y - 3y = 10x + 2y

A and B are not correct! We can't multiply the ys or the xs.

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Scorpion4ik [409]

Answer:uh what?

Step-by-step explanation:

8 0
3 years ago
Read 2 more answers
Simplify the expression and identify which property is used in each step.
777dan777 [17]

Answer:

1.2

Step-by-step explanation:

(0.85 + 0.50 + 0.15) - 0.30           Given

Simplify by adding in the parentheses first

(0.85 + 0.50 + 0.15) - 0.30

(1.35 + 0.15) - 0.30

(1.5) - 0.30

Subtraction Property

1.5 - 0.30

1.2

7 0
3 years ago
NEED HELP FAST
juin [17]

Answer:

-24 2/7

Step-by-step explanation:

-180 4/7 -166 2/7

-180 -166 = -24

4/7-2/7 = 2/7

-24 2/7

3 0
3 years ago
On average, a commercial airplane burns about 3.9 × 10³ mL of gasoline per second. There can be as many as 5.1 × 10³ airplanes i
motikmotik

3.9 x 5.1 = 19.89

10^3 x 10^3 = 10^6

19.89 x 10^6

move decimal point

1.989 x 10^7

4 0
3 years ago
Sinx = 1/2, cosy = sqrt2/2, and angle x and angle y are both in the first quadrant.
Leviafan [203]

Answer:

Option D. 3.73​

Step-by-step explanation:

we know that

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

and

sin^{2}(\alpha)+cos^{2}(\alpha)=1

step 1

Find cos(X)

we have

sin(x)=\frac{1}{2}

we know that

sin^{2}(x)+cos^{2}(x)=1

substitute

(\frac{1}{2})^{2}+cos^{2}(x)=1

cos^{2}(x)=1-\frac{1}{4}

cos^{2}(x)=\frac{3}{4}

cos(x)=\frac{\sqrt{3}}{2}

step 2

Find tan(x)

tan(x)=sin(x)/cos(x)

substitute

tan(x)=1/\sqrt{3}

step 3

Find sin(y)

we have

cos(y)=\frac{\sqrt{2}}{2}

we know that

sin^{2}(y)+cos^{2}(y)=1

substitute

sin^{2}(y)+(\frac{\sqrt{2}}{2})^{2}=1

sin^{2}(y)=1-\frac{2}{4}

sin^{2}(y)=\frac{2}{4}

sin(y)=\frac{\sqrt{2}}{2}

step 4

Find tan(y)

tan(y)=sin(y)/cos(y)

substitute

tan(y)=1

step 5      

Find tan(x+y)

tan(x+y)=\frac{tan(x)+tan(y)}{1-tan(x)tan(y)}

substitute

tan(x+y)=[1/\sqrt{3}+1}]/[{1-1/\sqrt{3}}]=3.73

7 0
3 years ago
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