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Oliga [24]
3 years ago
5

O

Mathematics
1 answer:
xxTIMURxx [149]3 years ago
7 0

Answer:

Dont know

Step-by-step explanation:

I dont know Archer's equation but the answer for Jenna equatiok is x=10

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Given h(x) = x2 – 5x + 7, find the following.<br> a. h(2)<br> b.h(-5)<br> c. h(-8)
azamat

Answer:

Step-by-step explanation:

hello :

h(x) = x² – 5x + 7

h(-2) = (-2)² – 5(-2) + 7 =4+10+7 =21

h(-5) = (-5)² – 5(-5) + 7= 25+25+7 =57

h(-8) = (-8)² – 5(-8) + 7 = 64+40+7=111

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3 years ago
Andrea spins the arrow on the spinner one time.
insens350 [35]

My Answer for your question is

A. O

4 0
3 years ago
Find the unknown sizes of angles in the following figure:​
8090 [49]

Answer:

angle x is 86

angle y is 38

Step-by-step explanation:

7 0
2 years ago
When fishing off the shores of Florida, a spotted seatrout must be between 10 and 30 inches long before it can be kept; otherwis
Mademuasel [1]

Answer:

There is a 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by

Z = \frac{X - \mu}{\sigma}

After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X. Subtracting 1 by the pvalue, we This p-value is the probability that the value of the measure is greater than X.

In this problem, we have that:

The lengths of the spotted seatrout that are caught, are normally distributed with a mean of 22 inches, and a standard deviation of 4 inches, so \mu = 22, \sigma = 4.

What is the probability that a fisherman catches a spotted seatrout within the legal limits?

They must be between 10 and 30 inches.

So, this is the pvalue of the Z score of X = 30 subtracted by the pvalue of the Z score of X = 10

X = 30

Z = \frac{X - \mu}{\sigma}

Z = \frac{30 - 22}{4}

Z = 2

Z = 2 has a pvalue of 0.9772

X = 10

Z = \frac{X - \mu}{\sigma}

Z = \frac{10 - 22}{4}

Z = -3

Z = -3 has a pvalue of 0.00135.

This means that there is a 0.9772-0.00135 = 0.97585 = 97.585% probability that a fisherman catches a spotted seatrout within the legal limits.

3 0
3 years ago
A restaurant charges an automatic gratuity of 18% on tables with more than 6 people. A party of 8 had a bill of p. Which express
nexus9112 [7]
Adding 18% gratuity to the cost means that you'll be paying 100% of the cost p <em>plus</em> 18% of that cost, or 108% of p total.

As an expression: 1.08p
8 0
3 years ago
Read 2 more answers
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