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Nataly [62]
4 years ago
14

Eliza's backpack weighs 18 and StartFraction 7 over 9 EndFraction pounds with her math book in it. Without her math book, her ba

ckpack weighs 14 and StartFraction 7 over 8 EndFraction pounds. How much does Eliza's math book weigh?
Mathematics
2 answers:
ddd [48]4 years ago
8 0

Answer:

3 65/72 pounds.

Step-by-step explanation:

My auntie's a math teacher so I went on her database to find the correct answer. (she went to every grade school elementary, middle, and high)

alexgriva [62]4 years ago
4 0
Her math book ways 3.9027 pounds or 3 65/72 pounds.
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Answer and Step-by-step explanation:

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3 years ago
Determine whether the sequence below is a geometric sequence and, if so, find a formula that describes the sequence.
Ierofanga [76]
<span>2, 4, 8, 16, –32, 64, …

Common ratio = 4/2 = 2

16/8 = 2

But -32/16 = -2.

The ratio is not constant, hence it is not a geometric.

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7 0
3 years ago
Question 19 (5 points) ✔ Saved
zheka24 [161]

The order of temperature values become -16.7°C > -11.15°C > -7°C > 3°C And -16.7°C is the coolest temperature and 3°C is the warmest as compare to others.

According to the statement

we have given that the some values of the temperatures and we have to write it in the order from the coolest to the warmest means in increasing order.

So, For this purpose,

The given values of temperatures are:

3°C , -7°C , 2°F, 262 K

Firstly convert into one form

So, convert all values in Celsius form,

3°C = 3°C

-7°C = -7°C

2°F = -16.7°C

262 K = -11.15°C

Now arrange into the order from coolest to warmest

So, it will become

-16.7°C > -11.15°C > -7°C > 3°C

So, -16.7°C is the coolest temperature and 3°C is the warmest as compare to others.

The order of temperature values become -16.7°C > -11.15°C > -7°C > 3°C And -16.7°C is the coolest temperature and 3°C is the warmest as compare to others.

Learn about the increasing order here

brainly.com/question/14662181

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7 0
1 year ago
Shenelle has 100100100 meters of fencing to build a rectangular garden. the garden's area (in square meters) as a function of th
cluponka [151]
Area as a function of width, w is:
a(w)=(w-25)^2+625
for maximum area, the width will be:
a'(w)=2(w-25)+0=0
solving for w we egt
2w-50=0
2w=50
w=25 m
given that the perimeter is 100, the length will be:
100=2(L+W)
solving for L we get:
L=50-W
but W=25m
hence
L=50-25=25 m
thus the maximum area will be:
A=L*W=25*25=625m^2

8 0
3 years ago
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