Question

WHY CAN'T ANYONE HELP ME? Twice last​ month, Judy Carter rented a car in​ Fresno, California, and traveled around the Southwest on business. The car rental agency rents its cars for a daily​ fee, plus an additional charge per mile driven. Judy recalls that her first trip lasted 4​ days, she drove 440 ​miles, and the rental cost her ​$286. On her second business trip she drove 190 miles in 3​ days, and paid ​$165.50 for the rental. Find the daily fee and the mileage charge.

Answer 1

Answer:

The daily rate is $33 and the per mile rate is $0.35

Step-by-step explanation:

4x + 440y = 286

3x + 190y = 165.5

We can solve this systems of equations by multiplying the second statement by $-\frac{4}{3}$ to try and eliminate the x variable.

4x + 440y = 286

-4x - $\frac{760}{3}$y = -220$\frac{2}{3}$

$\frac{560}{3}$ y= $\frac{196}{3}$

560y = 196

y = 0.35

So, the rate per mile is 0.35. Now, with this info, let's find the daily rate by plugging it into the equation.

$4x + 440\cdot0.35 = 286\\4x + 154 = 286\\4x = 132\\x = 33$

So, the daily rate is $33 and the mile rate is $0.35.

Hope this helped!

Answer 2

Answer:

the daily fee =33 dollars

and the mileage charge.=0.35

let d: be daily fee and m for mileage

cost of rental =(d*number of days)+ (m*number of mileage)

her first trip: 4d+440m=286

her second trip: 3d+190m=165.5

solve by addition and elimination

4d+440m=286 ⇒ multiply by 3 ⇒12d +1320m=(3)286

3d+190m=165.5⇒ multiply by 4⇒12d+190(4)m=4(165.5)

12d+1320m=858

12d+760m=662

subtract two equation to eliminate d

12d+1320m-12d-760m=858-662

560m=196

m=7/20=0.35 for on mileage

d: 4d+440m=286

4d=286-440(0.35)

d=(286-154)/4 33 dollars