Answer:
Colin has <em>8 sheets </em>left for his third class.
Step-by-step explanation:
Given that:
Total Number of pieces of papers = 
Number of pieces of papers used for 1st class = 5 fewer than half of the pieces in the pad
Writing the equation:

Also, Given that number of pieces of papers used for the 2nd class are 2 more than that of papers used in the 1st class.

Now, number of pieces of papers left for the third class = Total number of pieces of papers in the pad - Number of pieces of papers used in the first class - Number of pieces of papers used in the first class

So, the answer is:
Colin has <em>8</em> <em>sheets </em>left for his third class.
I believe it is (2+2) × (3+3)
5 * 12 = 60 (for the whole area)
3 * 2 = 6 (for the missing space)
6 + 2 = 8
12 - 8 = 4
4 * 3 = 12
12 / 2 = 6
6 + 6 = 12
60 - 12 = 48
Answer: 48
Sorry if this isn’t right :(
Answer:
Your equation is:
(x−5)2+(y+8)2=92
Expanding from general form you can write this as:
x2−10x+y2+14y+−8=0
Step-by-step explanation:
i think its correct ig don't know sry but i tried hope it helps you ✨