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boyakko [2]
4 years ago
8

The price of a cup of coffee was $2.65 yesterday. today, the price fell to $2.50 . find the percentage decrease. round your answ

er to the nearest tenth of a percent.
Mathematics
1 answer:
sergejj [24]4 years ago
8 0
We must find the difference between prices. $2.65 - $2.50 = $0.15. Now we need to calculate what percent $0.15 is of $2.65. It is 5.7%! The price decreased, so it is a 5.7% decrease!
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Please help meeee! please
ser-zykov [4K]

Answer:

A) 48.8

Step-by-step explanation:

the mean is: sum of all terms divided by number of terms

49 + 37 + 41 + 54 + 63= 244

244/ 5= 48.8

7 0
4 years ago
Based on the diagram, what is the value of x?
Fynjy0 [20]
Hope this helps! feel free to clarify

8 0
3 years ago
A bank offers all savings accounts 5% interest compounded annually. If one account has a principal of $100 and another
arsen [322]

Answer:

From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days .

Step-by-step explanation:

Given as :

The principal for the first account = p = $100

The rate of interest = r = 5% compounded annually

The account gets double , so, Amount = A = $200

Let the time after which account gets double = t years

So<u>, From Compound Interest method</u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

As amount is double its principal

So, A = 2 × $100 = $200

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

Or, $200 = $100 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{200}{100} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

<u>Again </u>

Amount = Principal × (1+\dfrac{\trxtrm rate}{100})^{\textrm time}

Or, A = p × (1+\dfrac{\trxtrm r}{100})^{\textrm t}

As amount is double its principal

So, A = 2 × $1000 = $2000

Or, $2000 = $1000 × (1+\dfrac{\trxtrm 5}{100})^{\textrm t}

Or, \dfrac{2000}{1000} = (1.05)^{\textrm t}

Or, 2 = (1.05)^{\textrm t}

Taking Log both side

Log_{10}2 = Log_{10}(1.05)^{t}

Or, 0.3010 = t Log_{10}1.05

Or, 0.3010 = t × 0.0211

∴ t = \dfrac{0.3010}{0.0211}

I.e t = 14.26

So, The time period to get account double is 14 years 26 days

Hence From the calculation for both the accounts, it is clear that both the account double in the same time period of 14 years 26 days . Answer

7 0
3 years ago
which of the following expresses the possible number of positive real solutions for the polynomial equation shown below
Nookie1986 [14]

The polynomial equation <u>x³ - 4x² - 7x + 28 = 0</u>, has solutions <u>-√7, √7,</u> and <u>4</u>, among which <u>√7</u> and <u>4</u> are positive real solutions. Hence we have two positive real solutions. Hence, <u>option D</u> is the right choice.

In the question, we are asked for the number of positive real solutions for the polynomial equation, x³ - 4x² - 7x + 28 = 0.

To find the solutions, we do as follows:

x³ - 4x² - 7x + 28 = 0,

or, (x³ - 7x) - (4x² + 28) = 0 {Grouping},

or, x(x² - 7) - 4(x² - 7) = 0 {Taking common},

or, (x - 4)(x² - 7) = 0 {Grouping},

or, (x - 4)(x + √7)(x - √7) = 0 {Using the formula: a^2 - b^2 = (a+b)(a-b)}.

By the zero-product rule, the solutions are:

x - 4 = 0, or, x = 4,

x + √7 = 0, or, x = -√7,

x - √7 = 0, or, x = √7.

Thus, the positive real solutions are 4, and √7. Hence, there are two positive real solutions.

Thus, the polynomial equation <u>x³ - 4x² - 7x + 28 = 0</u>, has solutions <u>-√7, √7,</u> and <u>4</u>, among which <u>√7</u> and <u>4</u> are positive real solutions. Hence we have two positive real solutions. Hence, <u>option D</u> is the right choice.

Learn more about polynomials at

brainly.com/question/1550365

#SPJ4

The complete question is:

"Which of the following expresses the possible number of positive real solutions for the polynomial equation shown below?

x³-4x²-7x+28=0

a. two or zero

b. three or one

c. one

d. two"

5 0
2 years ago
If Jan jogged 7x - 12 miles and Julie jogged 35x - 60miles , how many times longer was Julie's travel distance than Jan's?
OLEGan [10]

Answer:

Julie jogged five times further than Jan.

Step-by-step explanation:

We can find this solution just by dividing Julie's distance by Jan's:

\frac{35x - 60}{ 7x - 12} \\\\= \frac{5(7x - 12)}{ 7x - 12} \\\\= 5

So Julie jogged five times further.

5 0
3 years ago
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