Answer:
a.
2Al + 6HCl--> 2AlCl3 + 3H2
b.
take the atomic mass of Al =27.0, Cl = 35.5, and H= 1.0,
no. of moles = .mass / molar mass
no. of moles of Al placed = 2.7 / 27.0
=0.1 mol
Assuming Al is limiting (because the concentration nor volume of HCl solution is given).
From the equation, the mole ratio of Al : AlCl3 = 2:2 = 1: 1,
meaning for each 1 mole of Al reacted, it gives out 1 mole of AlCl3. This also means the no. of moles of Al reacted equals to the no. of moles of AlCl3 produced, which is 0.1 mole.
mass = no. of moles x molar mass
hence,
mass of AlCl3 produced = 0.1 / (27 + 35.5x3)
= 0.00075 g
c. since this question is unclear, and the concentration nor volume of HCl solution is given, part c cannot be answered. Please let me know if you have any more info regarding it! thanks :)
d. From the equation, the mole ratio of Al:H2 = 2:3, meaning every 2 moles of Al reacted, gives out 3 moles of hydrogen.
using this ratio, no. of moles of H2 produced will = 0.1 x 3 / 2
=0.15 mol
At STP, the molar volume of gas is 22.4 dm3 mol-1,
volume = no. of moles x molar volume
hence volume of H2 obtained = 0.15 x 22.4
= 3.36 dm3
