<span>The percent composition of s in the compound is 44.4%.
</span>
No. of grams of ca = 15
no. of grams of S = 12
<span>percent composition of s in the compound = 12/(15 + 12) x 100
= 12/27 x 100
= 0.44 x 100
= 44.4%</span>
<span>Mass oxigen = 2.81 - 2.50 = 0.31 g
Moles O = 0.31 g / 15.9994 g/mol =0.0194
moles Cu = 2.50 g / 63.546 g/mol =0.0393
we divide by the smallest number
0.0194 / 0.0194 = 1 => O
0.0393 / 0.0194 = 2 => Cu
the formula is Cu2O ( Copper (I) oxide )
Ya got this</span>
Answer:
Breaking down of food substances without oxygen
Explanation:
The release of energy by breaking down food substances in the absence of oxygen
Quantitative data can be counted, measured, and expressed using numbers. Qualitative data is descriptive and conceptual.
Answer:
Chemical reactivity increases down a group and decreases from left to right of a period.
Explanation:
The higher the ionization energy is, the lower the reactivity is. Since the ionization energy is highest in the top right corner of the periodic table, we can assume that the most reactive elements are in the opposite bottom left corner. This is because the electrons that react are farther away from the nucleus thus experience less attraction to the nucleus (called nuclear shielding). Therefore their electrons are more easily removed than elements that don't ecperience nuclear shielding.
