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3 years ago

14

I need help with this

2 answers:

S_A_V [24]3 years ago

5 0

Answer:

that answer is 1

Step-by-step explanation:

USE A GRAPH

disa [49]3 years ago

5 0

Answer:

idk how to answer it but I try it it was a lil confused

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What is the equation of the circle whose diameter has endpoints (8,-2) and (-2,6)?

klemol [59]

Answer:

$(x-3)^{2} +(y-2)^{2}=41$

Step-by-step explanation:

step 1

Find the diameter of the circle

the formula to calculate the distance between two points is equal to

$d=\sqrt{(y2-y1)^{2}+(x2-x1)^{2}}$

we have

$A(8,-2)\\E(-2,6)$

substitute the values

$d=\sqrt{(6+2)^{2}+(-2-8)^{2}}$

$d=\sqrt{(8)^{2}+(-10)^{2}}$

$d=\sqrt{164}\ units$

$d=2\sqrt{41}\ units$

step 2

Find the center of the circle

The center is the midpoint of the diameter

The center is equal to

$C=(\frac{8-2}{2},\frac{-2+6}{2})$

$C=(3,2)$

step 3

Find the equation of the circle

The equation of the circle in center radius form is equal to

$(x-h)^{2} +(y-k)^{2}=r^{2}$

we have

(h,k)=(3,2)

$r=2\sqrt{41}/2=\sqrt{41}\ units$ ---> the radius is half the diameter

substitute

$(x-3)^{2} +(y-2)^{2}=(\sqrt{41})^{2}$

$(x-3)^{2} +(y-2)^{2}=41$

4 0

3 years ago

If x = 7+3 root 5 by 7 - 3 root 5 , find the value of x^2 + 1 by x^2

Vesnalui [34]

Answer:

6 because why not

Step-by-step explanation:

6 0

2 years ago

Hey Bestie! 50 pts Pls help! Real answers only pls <3

frosja888 [35]

Answer:

$1. \: 3i$

2. option D

3. option C

4. option D

5. option C

6. option B

7. option C

8. option D

9. option C

10. option C

Step-by-step explanation:

<h2> $1. \: \sqrt{ - 9}$ </h2>

$\sqrt{ - 1(9)}$

$\sqrt{ - 1} \times \sqrt{ 9}$

$i \times \sqrt{9}$

$i \times \sqrt{ {3}^{2} }$

$i \times 3$

$3i$

<h2> $2. \: \sqrt{ - 8}$ </h2>

$\sqrt{ - 1(8)}$

$\sqrt{ - 1} \times \sqrt{8}$

$i \times \sqrt{8}$

$i \times \sqrt{ {2}^{2} \times 2 }$

$2i \sqrt{2}$

<h2> $3. \: \sqrt{ - 80}$ </h2>

$\sqrt{ - 1} \times \sqrt{80}$

$i \times \sqrt{80}$

$4i \: \sqrt{5}$

<h2> $4. \: \sqrt{ - 75}$ </h2>

$\sqrt{ - 1} \times \sqrt{75}$

$i \times \sqrt{75}$

$i \times \sqrt{ {5}^{2} \times 3 }$

$5i \sqrt{3}$

<h2> $5. \: \sqrt{ - 72}$ </h2>

$\sqrt{ - 1} \times \sqrt{72}$

$i \times \sqrt{72}$

$i \times ( {6}^{2} \times 2)$

$6i \sqrt{2}$

<h2> $6. \sqrt{ - 20}$ </h2>

$\sqrt{ - 1} \times \sqrt{20}$

$i \times \sqrt{20}$

$i \times \sqrt{ {2}^{2} \times 5}$

$2i \sqrt{5}$

<h2> $7. \: \sqrt{ - 27}$ </h2>

$\sqrt{ - 1} \times \sqrt{27}$

$i \times \sqrt{27}$

$i \times \sqrt{ {3}^{2} \times 3}$

$3i \sqrt{3}$

<h2> $8. \: \sqrt{ - 12}$ </h2>

$\sqrt{ - 1 \times 12}$

$i \times \sqrt{12}$

$i \times \sqrt{4(3)}$

$2i \sqrt{3}$

<h2> $9. \: \sqrt{ - 125}$ </h2>

$\sqrt{ - 1} \times \sqrt{125}$

$i \times \sqrt{ {5}^{2} \times 5 }$

$5i \sqrt{5}$

<h2> $10. \: \sqrt{ - 180}$ </h2>

$\sqrt{ - 1} \times \sqrt{180}$

$i \times \sqrt{ {6}^{2} \times 5 }$

$6i \sqrt{5}$

<h3>Hope it is helpful...</h3>

5 0

2 years ago

PLEASE HELP!!!!!! CORRECT ANSWER GETS BRAINLIEST

Gemiola [76]

I solved it this way. I’m guessing you should replace the zeros with these numbers here.

4 0

3 years ago

2(5x+4)-3x<br>Only for Best users.

OlgaM077 [116]

Answer:

7x+8

Step-by-step explanation:

2(5x+4)-3x

distribute: 10x+8-3x

=7x+8

6 0

2 years ago

Read 2 more answers