Given:
pool length : 10 yards
pool width : 8 yards
Area = 10 yds * 8 yds = 80 yd²
(10 + 2x)(8 + 2x) = 120
10(8 + 2x) + 2x(8+2x) = 120
80 + 20x + 16x + 4x² = 120
4x² + 36x + 80 - 120 = 0
4x² + 36x - 40 = 0
4(x² + 9x - 10) = 0
4(x + 10)(x - 1) = 0
x + 10 = 0
x = -10
x - 1 = 0
x = 1
the width of the deck is 1 yard
Answer:
metals or metalloids
Step-by-step explanation:
I'm built different i dont know if im right about the question. im just not sure if i understood the question correctly
Answer:
8 in
Step-by-step explanation:
Area = (diagonal 1 x diagonal 2)/2
60 = (diagonal 1 x 15)/2
60 x 2 = diagonal 1 x 15
120 = diagonal 1 x 15
diaognal 1 = 120/15 = 8
Hopes this help:
Answer: x = 3, -2 & y = 5, 0
Hopes this is the answer that you where looking for if not I am so sorry.
Please write your points by enclosing the x- and y-components inside parentheses: (2, 4) and (7,2). Use the distance formula. Do you know it?
Distance between (2,4) and (7,2) is Sqrt ( [7-2]^2 + [2-4]^2 )
Note: by "Quasstion" you most likely meant "question."
