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3 years ago

In order for a person to "see" an object, light waves pass through the ___________.

2 answers:

8 0

I think the correct answer from the choices listed above is the first option. In order for a person to "see" an object, light waves pass through the cornea. The cornea is the transparent layer forming at the front of the eye. Hope this answers the question. Have a nice day.

Marta_Voda [28]3 years ago

3 0

Answer: Cornea

Explanation:

Cornea is a transparent outer surface of the eye. It covers the inner parts of the eye ball. It is the first part of the eye through which the light enters the eye. The refractive power of the cornea bends the incident light rays, in such a way that they pass through the pupil. From pupil the light enters the opening of the iris through which the light enters the eye. The iris is like shutter of a camera. It regulates the amount of light entering the eye.

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Which statement best describes a scientific law?

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3 years ago

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Serggg [28]

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3 years ago

What is the velocity of a 50kg skater if her momentum is 225kg. m/s?

Gnom [1K]

|Momentum| = (mass) x (speed)

225 kg-m/s =(50kg) x (speed)

Divide each side by (50kg): Speed=(225 kg-m/s) / (50 kg) = 4.5 m/s .

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3 years ago

Read 2 more answers

A uniform rod of length L is pivoted at L/4 from one end. It is pulled to one side through a very small angle and allowed to osc

ludmilkaskok [199]

Answer:

T= 4.24sec

Explanation:

We are going to use the formula below to calculate.

$T=2\pi \sqrt{\frac{L}{g} }$

Where T is period

L is length of rod

g is acceleration due to gravity = $9.8m/s^{2}$

From the problem, the rod is pivoted at 1/4L which means that three quarter of the rod was used for the oscillation. lets call this $L_{O}$

$L_{O} = 3/4 * 5.95m$

= 4.4625m

thus $T=2\pi \sqrt{\frac{L_{O} }{g} }$

$T=2\pi \sqrt{\frac{4.4625 }{9.8} }$

T= 4.24sec

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3 years ago

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Anna007 [38]

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3 years ago