The mass m of the object = 5.25 kg
<h3>Further explanation</h3>
Given
k = spring constant = 3.5 N/cm
Δx= 30 cm - 15 cm = 15 cm
Required
the mass m
Solution
F=m.g
Hooke's Law
F = k.Δx
![\tt m.g=k.\Delta x\\\\m.10=3.5\times 15\\\\m=5.25~kg](https://tex.z-dn.net/?f=%5Ctt%20m.g%3Dk.%5CDelta%20x%5C%5C%5C%5Cm.10%3D3.5%5Ctimes%2015%5C%5C%5C%5Cm%3D5.25~kg)
The magnitude of the force that the beam exerts on the hi.nge will be,261.12N.
To find the answer, we need to know about the tension.
<h3>How to find the magnitude of the force that the beam exerts on the hi.nge?</h3>
- Let's draw the free body diagram of the system using the given data.
- From the diagram, we have to find the magnitude of the force that the beam exerts on the hi.nge.
- For that, it is given that the horizontal component of force is equal to the 86.62N, which is same as that of the horizontal component of normal reaction that exerts by the beam on the hi.nge.
![N_x=86.62N](https://tex.z-dn.net/?f=N_x%3D86.62N)
- We have to find the vertical component of normal reaction that exerts by the beam on the hi.nge. For this, we have to equate the total force in the vertical direction.
![N_y=F_V=mg-Tsin59\\](https://tex.z-dn.net/?f=N_y%3DF_V%3Dmg-Tsin59%5C%5C)
- To find Ny, we need to find the tension T.
- For this, we can equate the net horizontal force.
![F_H=N_x=Tcos59\\\\T=\frac{F_H}{cos59} =\frac{86.62}{0.51}= 169.84N](https://tex.z-dn.net/?f=F_H%3DN_x%3DTcos59%5C%5C%5C%5CT%3D%5Cfrac%7BF_H%7D%7Bcos59%7D%20%3D%5Cfrac%7B86.62%7D%7B0.51%7D%3D%20169.84N)
- Thus, the vertical component of normal reaction that exerts by the beam on the hi.nge become,
![N_y= (40*9.8)-(169.8*sin59)=246.4N](https://tex.z-dn.net/?f=N_y%3D%20%2840%2A9.8%29-%28169.8%2Asin59%29%3D246.4N)
- Thus, the magnitude of the force that the beam exerts on the hi.nge will be,
![N=\sqrt{N_x^2+N_y^2} =\sqrt{(86.62)^2+(246.4)^2}=261.12N](https://tex.z-dn.net/?f=N%3D%5Csqrt%7BN_x%5E2%2BN_y%5E2%7D%20%3D%5Csqrt%7B%2886.62%29%5E2%2B%28246.4%29%5E2%7D%3D261.12N)
Thus, we can conclude that, the magnitude of the force that the beam exerts on the hi.nge is 261.12N.
Learn more about the tension here:
brainly.com/question/28106871
#SPJ1
Answer:
So do 2400 divided by 70. I got 34.285714 and the numbers behind the decimal are repeating. If you round it you get 34.3
3260÷4=815 which is you average seed