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3 years ago

How does a plane and parachute manipulate air resistance differently?

1 answer:

3 0

A planes wings are slightly tilted catching the air as it passes, keeping it afloat
a parachute has a cupping effect where it can only take so much, so it slows down your descendence

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What happens to the wavelength as the frequency of a whale noise changes from 200hz to 300hz

rewona [7]

Answer:

When there is an increase in the frequency of sound waves, the wavelength decreases.

Explanation:

Given data,

The frequency of the whale changes from 200 Hz to 300 Hz

The formula for frequency and wavelength is,

λ = v/f

Where v is the velocity of the sound waves in water (1531 m/s)

The wavelength at 200 Hz is,

λ = 1531/200

= 7.655 m

The wavelength at 300 Hz is,

λ = 1531/300

= 5.1 m

Hence, when there is an increase in the frequency of sound waves, the wavelength decreases.

4 0

3 years ago

Help????????????????

Naddik [55]

Answer:

23.5

Explanation:

Dunno how 2 explain but this is correct 4 sureeeeee.

6 0

3 years ago

A current of 32.1 mA flows in a silver wire of diameter 4.57 mm. Find the electric field strength inside the wire. The conductiv

joja [24]

Answer:

$E = \rho J = 3.13\times 10^{-5} ~{\rm N/m}$

Explanation:

The relationship between the current and the electric field inside a wire is given by the following equation:

$\rho = \frac{E}{J}$

where ρ is the resistivity, and J is the current density. The current density is the current per area:

$J = \frac{I}{A} = \frac{31.2 \times 10^{-3}}{\pi (\frac{4.57 \times 10^{-3}}{2})^2} = 1957$

The resistivity is the reciprocal of conductivity. Therefore,

$\rho = \frac{1}{6.25 \times 10^7} = 1.6 \times 10^{-8}$

Finally, the electric field can be found:

$E = \rho J = 3.13\times 10^{-5} ~{\rm N/m}$

8 0

3 years ago

If gravity on the earth increased, what affect would it have on the moon

Rufina [12.5K]

Answer:

If gravity on Earth is increased, this gravitational tugging would have influenced the moon's rotation rate. If it was spinning more than once per orbit, Earth would pull at a slight angle against the moon's direction of rotation, slowing its spin. If the moon was spinning less than once per orbit, Earth would have pulled the other way, speeding its rotation.

6 0

3 years ago

A 28.0 kg child plays on a swing having support ropes that are 2.30 m long. A friend pulls her back until the ropes are 45.0 ∘ f

Dimas [21]

Answer

A)184.9J

B)=3.63m/s

C) Zero

Explanation:

A)potential energy of the child at the initial position, measured relative the her potential energy at the bottom of the motion, is

U=Mgh

Where m=28kg

g= 9.8m/s

h= difference in height between the initial position and the bottom position

We are told that the rope is L = 2.30 m long and inclined at 45.0° from the vertical

h=L-Lcos(x)= L(1-cosx)=2.30(1-cos45)

=0.674m

Her Potential Energy will now

= 28× 9.8×0.674

=184.9J

B)we can see that at the bottom of the motion, all the initial potential energy of the child has been converted into kinetic energy:

E= 0.5mv^2

where

m = 28.0 kg is the mass of the child

v is the speed of the child at the bottom position

Solving the equation for v, we find

V=√2k/m

V=√(2×184.9/28

=3.63m/s

C)we can find work done by the tension in the rope is given using expresion below

W= Tdcosx

where W= work done

T is the tension

d = displacement of the child

x= angle between the directions of T and d

In this situation, we have that the tension in the rope, T, is always perpendicular to the displacement of the child, d. x= 90∘ and cos90∘=0 hence, the work done is zero.

6 0

3 years ago