Answer:
The equivalent will be:
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D%3D%5Cleft%28%5C%3Ax%5E%7B%5Cfrac%7B2%7D%7B7%7D%7D%5Cright%29%5Cleft%28y%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%5Cright%29)
Therefore, option 'a' is true.
Step-by-step explanation:
Given the expression
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D)
Let us solve the expression step by step to get the equivalent
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D)
as
∵ ![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)



also
∵ ![\mathrm{Apply\:radical\:rule}:\quad \sqrt[n]{a}=a^{\frac{1}{n}}](https://tex.z-dn.net/?f=%5Cmathrm%7BApply%5C%3Aradical%5C%3Arule%7D%3A%5Cquad%20%5Csqrt%5Bn%5D%7Ba%7D%3Da%5E%7B%5Cfrac%7B1%7D%7Bn%7D%7D)



so the expression becomes


∵ 
Thus, the equivalent will be:
![\frac{\sqrt[7]{x^2}}{\sqrt[5]{y^3}}=\left(\:x^{\frac{2}{7}}\right)\left(y^{-\frac{3}{5}}\right)](https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%5B7%5D%7Bx%5E2%7D%7D%7B%5Csqrt%5B5%5D%7By%5E3%7D%7D%3D%5Cleft%28%5C%3Ax%5E%7B%5Cfrac%7B2%7D%7B7%7D%7D%5Cright%29%5Cleft%28y%5E%7B-%5Cfrac%7B3%7D%7B5%7D%7D%5Cright%29)
Therefore, option 'a' is true.
Step-by-step explanation:
A.
Step 1 Divide: 128 ÷ 8.
Step 2 Divide: 96 ÷ 8.
Step 3 Subtract the two quotients.
is the right option
So on the first one, check the first picture, solve for "x" and "y" respectively
on the second one, check the second picture, the left-half, solve for "x"
on the last one, are they similar? check the second picture, right-half
Answer:
Step-by-step explanation: