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yarga [219]
4 years ago
11

Directions- Write a formula from the given day for each linear function Find the equation of the line parallel to 6x+3y-11=0, th

at god through the point (-2,5).
Mathematics
1 answer:
lukranit [14]4 years ago
4 0

Answer:

y = -3x-1 or 3x + y = -1

Step-by-step explanation:

6x + 3y - 11 = 0 can be written as y = -3x + (11/3)

In parallel lines the slope remains the same but the constant changes. To find the constant you place in the cordinates for x and y.

5 = -3(-2) + b

5 = 6 + b

5 - 6 = b

-1 = b

Now you replace (11/3) by the new b, -1

y = -3x - 1

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Checking for a perfect cube :
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4.3 Factoring: 3x3 + 8x2 + 4x - 7
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Group 2: 8x2 + 4x
Pull out from each group separately :
Group 1: (3x3 - 7) • (1)
Group 2: (2x + 1) • (4x)

Please 5 star and like. Appreciated
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