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yarga [219]
3 years ago
11

Directions- Write a formula from the given day for each linear function Find the equation of the line parallel to 6x+3y-11=0, th

at god through the point (-2,5).
Mathematics
1 answer:
lukranit [14]3 years ago
4 0

Answer:

y = -3x-1 or 3x + y = -1

Step-by-step explanation:

6x + 3y - 11 = 0 can be written as y = -3x + (11/3)

In parallel lines the slope remains the same but the constant changes. To find the constant you place in the cordinates for x and y.

5 = -3(-2) + b

5 = 6 + b

5 - 6 = b

-1 = b

Now you replace (11/3) by the new b, -1

y = -3x - 1

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2 years ago
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8 0
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