Question

Directions- Write a formula from the given day for each linear function Find the equation of the line parallel to 6x+3y-11=0, that god through the point (-2,5).

Answer 1

Answer:

y = -3x-1 or 3x + y = -1

Step-by-step explanation:

6x + 3y - 11 = 0 can be written as y = -3x + (11/3)

In parallel lines the slope remains the same but the constant changes. To find the constant you place in the cordinates for x and y.

5 = -3(-2) + b

5 = 6 + b

5 - 6 = b

-1 = b

Now you replace (11/3) by the new b, -1

y = -3x - 1