To solve the exercise it is necessary to take into account the definition of speed as a function of distance and time, and the speed of air in the sound, as well

Where,
V= Velocity
d= distance
t = time
Re-arrange the equation to find the distance we have,
d=vt
Replacing with our values


It is understood that the sound comes and goes across the entire lake therefore, the length of the lake is half the distance found, that is



Therefore the length of the lake is 634,55m
Seems to me that it flies 400 m/s there and 600 m/s back the same distance.
therefore the average of 400 and 600 is 500 m/s. The distance is the same so the normal formula of (d2-d1)/(t2-t1) is applicable.
Answer:
-4m/s²
Explanation:
a = Δv/t
Our change in velocity is equal to v₂-v₁, which in this equation is 0 m/s - 100 m/s, so our change in velocity is -100m/s. Now plug that and our time into the equation, like so:
a = (-100m/s)/(25s) a= -4m/s².
Answer:
all above
Explanation:
friction is necessary to live
Answer:
The answer is D 100 newton
Explanation:
2.0m/s2 is d acceleration while the 50kg is the mass. Force = mass x acceleration. So f=50x2.so force is 100 newton