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ExtremeBDS [4]
3 years ago
11

A thin film of transparent material in air has a refractive index of 1.50 and a thickness of 204 nm. For light incident normally

on the film, take interference into account to predict which (if any) wavelength(s) of light in the visible portion of the spectrum (400 nm to 700 nm) will be transmitted through the film particularly: i): well
ii): poorly
Physics
1 answer:
RoseWind [281]3 years ago
5 0

Answer:

612 nm wavelength will be properly transmitted and 306 nm  wavelength will be poorly transmitted.

Explanation:

Given that,

Refractive index = 1.50

Thickness = 204 nm

We need to calculate the wavelength

For interference due to transmitted light

2\mu t\cor r=m\lambda

Here, r = 0° , for normal incidence

2\mu t=m\lambda

For m = 1

2\times1.50\times204\times10^{-9}=1\times\lambda

\lambda=612\ nm

For m = 2

2\times1.50\times204\times10^{-9}=2\times\lambda

\lambda=\dfrac{2\times1.50\times204\times10^{-9}}{2}

\lambda=306\ nm

Hence, 612 nm wavelength will be properly transmitted and 306 nm  wavelength will be poorly transmitted.

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Explanation:

When the body has mass m

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a=F/m

Then,

When you the mass is quadruple

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Then, let assume you are applying the same force

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7 0
3 years ago
A wire 3.22 m long and 7.32 mm in diameter has a resistance of 11.9 mΩ. A potential difference of 33.7 V is applied between the
Scorpion4ik [409]

Answer:

(a) Current is 2831.93 A

(b) 8.40A/m^2

(c) \rho =15.52\times 10^{-9}ohm-m

Explanation:

Length of wire l = 3.22 m

Diameter of wire d = 7.32 mm = 0.00732 m

Cross sectional area of wire

A=\pi r^2=3.14\times 0.00366^2=4.20\times 10^{-5}m^2

Resistance R=11.9mohm=11.9\times 10^{-3}ohm

Potential difference V = 33.7 volt

(A) current is equal to

i=\frac{V}{R}=\frac{33.7}{11.9\times 10^{-3}}=2831.93A

(B) Current density is equal to

J=\frac{i}{A}

J=\frac{2831.93}{4.20\times 10^{-5}}=8.40A/m^2

(c) Resistance is equal to

R=\frac{\rho l}{A}

11.9\times 10^{-3}=\frac{\rho \times 3.22}{4.20\times 10^{-5}}

\rho =15.52\times 10^{-9}ohm-m

4 0
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In an emergency situation, firemen need to respond as quickly as possible. If a fireman is responding from the second floor, how
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8 0
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A galvanometer with a resistance of 40.0 ω deflects full scale at a current of 2.0 ma. what resistance should be used with this
kogti [31]
The resistance needed to be added is R
The Current is 2 ma
The voltage reading is a maximum of 50 volts.
The ma meter has an internal resistance of 40 ohms.

Formula
E = I * R

Givens
E = 50
I = 2 ms
R = R + 40

Solution
E = I * R
I = 2 ma [ 1 amp / 1000 ma] = 0.002 amp
50 = 0.002 * (R + 40)  Divide by 0.002
50/0.002 = R + 40
25000 = R + 40 Subtract 40 from both sides.
R = 25000 - 40
R = 24960     Answer

8 0
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Answer:

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