Question

7. The According to Wien’s Law (λmax = 3×106/T), what is the temperature of the radiation? Recall that to use this formula, the wavelength must be in nanometers (1nm = 10−9 m) and the temperature will be in Kelvin.

Answer 1

Answer:

According to Wien’s Law:

$\lambda_{peak} = \frac{2.9 \times 10^{6} }{T(K)}$

where;

$\lambda_{peak}$ is the wavelength

T(K) is the temperature in Kelvin

Putting the values given in the above equation:

${T(K)} = \frac{2.9 \times 10^{6} }{\lambda_{peak}}$

${T(K)} = \frac{2.9 \times 10^{6} }{3 \times 10^{3}}}$

T(K) = 0.966×$10^{3}$