All categories

2 years ago

Friction _____.

Physics

1 answer:

quester [9]2 years ago

8 0

Answer:

all above

Explanation:

friction is necessary to live

You might be interested in

Reeti has a mass of 51.0 kg. The Gravitron, a ride that spins so fast that the floor can be removed without the riders falling,

Serggg [28]

Answer:

L = 2774.4 $kgm^{2}/s$

Explanation:

Using the formula

L = mvr

Where L is angular momentum

m is mass

v is velocity

r is radius

m= 51kg , v=17m/s , r=3.2m

L = 51×17×3.2

L = 2774.4 $kgm^{2}/s$

7 0

2 years ago

A force of 20 N is exerted by an electric field on a test charge of 8.0 x 10² C at a point, P. What is the electric field streng

kenny6666 [7]

Answer:

the answer is equal to 1.6N/C

5 0

2 years ago

Which of these hazmat products are allowed in your FC?

aliina [53]

Answer: Hazmat products are allowed in your FC are:

A GPS unit (lithium batteries)
A subwoofer (magnetized materials)

Explanation:

Hazmat products consist of flammable, corrosive and harmful substances which are actually very hazardous to human health and environment.

Hazardous material allowed in FC are as follows.

Magnetized material products like as speakers.
Non-spillable battery products like toy cars.
Lithium-ion battery containing products like laptops, mobile phones etc.
Non-flammable aerosol.

So, hazmat allowed products are GPS unit (lithium batteries) and subwoofer (magnetized materials).

Thus, we can conclude that hazmat products are allowed in your FC are:

A GPS unit (lithium batteries)
A subwoofer (magnetized materials)

7 0

2 years ago

A smooth circular hoop with a radius of 0.800 m is placed flat on the floor. A 0.300-kg particle slides around the inside edge o

Marrrta [24]

Answer:

a)11.25 J

b)Number of revolution = 1

Explanation:

Given that

Radius ,r= 0.8 m

m= 0.3 kg

Initial speed ,u= 10 m/s

final speed ,v= 5 m/s

Initial energy

$KE_i=\dfrac{1}{2}mu^2$

$KE_i=\dfrac{1}{2}0.3\times 10^2$

KEi= 15 J

Final kinetic energy

$KE_f=\dfrac{1}{2}mv^2$

$KE_f=\dfrac{1}{2}0.3\times 5^2$

KEf=3.75 J

The energy transformed from mechanical to internal = 15 - 3.75 J = 11.25 J

The minimum value to complete the circular arc

$V=\sqrt{r.g}$

Now by putting the values

$V=\sqrt{0.8\times 10}$

V= 2.82 m/s

So kinetic energy KE

$KE=\dfrac{1}{2}mV^2$

$KE=\dfrac{1}{2}0.3\times 2.82^2$

KE=1.19 J

ΔKE= KEi - KE

ΔKE= 15- 1.19 J

ΔKE=13.80 J

The minimum energy required to complete 2 revolutions = 2 x 11.25 J

= 22.5 J

Here 22.5 J is greater than 13.8 J.So the particle will complete only one revolution.

Number of revolution = 1

4 0

2 years ago

Car A rear ends Car B, which has twice the mass of A, on an icy road at a speed low enough so that the collision is essentially

mixer [17]

Answer:

D. The momentum of Car B is three times as great in magnitude as that of car A.

Explanation:

I majored in Physics

3 0

2 years ago