Answer:
The answer to your question is letter c) 6.09 g of sodium and 9.38 g of chlorine.
Explanation:
This problem is solve using rule of three
We know that the proportion Sodium to Chloride is 1 to 1 in sodium chloride, so we have to look for this proportion in the options
AM Sodium = 23 g
AM Chlorine = 35.5 g
Sodium Chlorine
23 g ---------------- 1 mol 35.5 g -------------- 1 mol
1713.73g ------------- x 2666.6 g ------------- x
x = 1713.73/23 = 74.51 x = 2666.6/35.5 = 75.12
These values are very similar, we have to look for the proportion in the options
a) 6.09g of sodium = 0.26 mol
4,87 g of chlorine = 0.14 mol These numbers are not very similar
b) We have 0.26 mol of Na
0.037 mol of Cl This is not the answer
c) We have 0.26 mol of Na
0.26 mol of Cl These numbers are the same, the proportion is 1:1, this is the answer
d) We have 0.26 mol of Na
0.36 mol of Cl This is not the answer
