Question

Two samples of sodium chloride with different masses were decomposed into their constituent elements. One sample produced 1.731.73 g of sodium and 2.662.66 g of chlorine. Being consistent with the law of constant composition, also called the law of definite proportions or law of definite composition, which set of masses could be the result of the decomposition of the other sample?
a. 6.09 g of sodium and 4.87 g of chlorine.
b. 6.09 g of sodium and 1.33 g of chlorine.
c. 6.09 g of sodium and 9.38 g of chlorine.
d. 6.09 g of sodium and 12.8 g of chlorine.

Answer 1

Answer:

The answer to your question is letter c) 6.09 g of sodium and 9.38 g of chlorine.

Explanation:

This problem is solve using rule of three

We know that the proportion Sodium to Chloride is 1 to 1 in sodium chloride, so we have to look for this proportion in the options

AM Sodium = 23 g

AM Chlorine = 35.5 g

                 Sodium                                     Chlorine

           23 g ---------------- 1 mol              35.5 g -------------- 1 mol

       1713.73g -------------    x               2666.6 g -------------    x

          x = 1713.73/23 = 74.51                     x = 2666.6/35.5 = 75.12

    These values are very similar, we have to look for the proportion in the options

a)      6.09g of sodium = 0.26 mol

      4,87 g of chlorine = 0.14 mol           These numbers are not very similar

b) We have 0.26 mol of Na

                  0.037 mol of Cl                      This is not the answer

c) We have 0.26 mol of Na

                  0.26 mol of Cl                     These numbers are the same, the proportion is 1:1, this is the answer

d) We have 0.26 mol of Na

                   0.36 mol of Cl                    This is not the answer