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postnew [5]
3 years ago
8

What volume, in milliliters, of 2.0 calcium chloride stock solution would you use to make 500 ml of 0.300 m of calcium chloride

cacl2 solution?
Chemistry
1 answer:
mash [69]3 years ago
8 0
We can use the following formula when making diluted solutions from more concentrated solutions.
c1v1 = c2v2 
where c1 is the concentration and v1 is the volume of the concentrated solution 
and c2 is concentration and v2 is volume of the diluted solution to be prepared 

substituting these values in the equation 
2.0 M x V = 0.300 M x 500 mL 
V = 75 mL

75 mL should be taken from the stock solution and diluted upto 500 mL to make the 0.300 M solution 

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What mass of h2o is formed when h2 reacts with 384 grams of o2?
Tasya [4]
Answer is: mass of water is 432 grams.
Chemical reaction: 2H₂ + O₂ → 2H₂O.
m(O₂) = 384 g.
M(O₂) = 2 · 16 g/mol = 32 g/mol, molar mass.
n(O₂) = m(O₂) ÷ M(O₂).
n(O₂) = 384 g ÷ 32 g/mol.
n(O₂) = 12 mol, amount of substance.
From chemical reaction: n(O₂) : n(H₂O) = 1 : 2.
n(H₂O) = 12 mol · 2 = 24 mol.
m(H₂O) = n(H₂O) · M(H₂O).
m(H₂O) = 24 mol · 18 g/mol.
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8 0
3 years ago
A backpacker collects snow at 0°C, and places it in a cooking pot on a camp stove. It takes 643 kJ of heat energy to melt the sn
frutty [35]

Answer:

mass (m) of the snow that the backpacker collected= 0.855 kg

Explanation:

Given that:

Q = 643 kJ = 643000 J

ΔHfusion = 6.02 kJ/mol = 6020 J/mol

number of mole of water H2O = \frac{mass (m)}{18}

c = 4.18 J/g⋅K

ΔT = 100 K

Since there is a phase change from solid to liquid; then :

Q = Q_s + Q_l

ΔH = \frac{q}{mol}

However without the given mass; we substitute \frac{m}{18} for the number of moles; so:

Q = \delta H * \frac{m}{18} + m*c * \delta T

643000 =6020 * \frac{m}{18}+ m * 4.18 * 100

m = 855 g

m = 0.855 kg

mass (m) of the snow that the backpacker collected= 0.855 kg

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Help science worth 50 points
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I think this is like a game in which you need dice.

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