Answer:
2a^2 + 3a - 1 ,
Step-by-step explanation:
I am assuming you mean
2a^3-a^2-7a+2
By long division:
a - 2 ) 2a^3 - a^2 - 7a + 2 ( 2a^2 + 3a - 1 <------- Quotient
2a^3 - 4a^2
3a^2 - 7a
3a^2 - 6a
-a + 2
-a + 2
. . . . .
Answer:
option B (28/52)
Step-by-step explanation:
from probability
P(A∪B)=P(A)+P(B)-P(A∩B)
where
P(A∪B) = probability that event A or B happen
P(A∩B) = probability that event A and B happen simultaneously
P(A) = probability that event A happen
P(B) = probability that event B happen
the probability that the card is special or red
P( special or red)= P(special) + P(red) - P( special and red)
since
P(special)= 4/52
P(red) = 26/52
P( special and red) = 2/52
therefore
P( special or red)= 4/52 + 26/52 - 2/52 = 28/52
P( special or red)= 28/52
(option B)
Since 1/8000 is 0.000125, we can move the decimal 4 terms to the right.
So that will be 1.25 • 10^-4
Choice B
She has run 21 miles already. Let t be the number of additional miles added on.
In total, she has run t+21 miles
This is going to be set greater than 38 since "Ann will run more than 38 miles"
So we have this inequality
t+21 > 38
we solve for t by subtracting 21 from both sides
t+21 > 38
t+21-21 > 38-21
t+0 > 17
t > 17
The final answer is t > 17
which means that the possible additional number of miles she could run is anything larger than 17. So t = 18 is one possibility.
