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Rom4ik [11]
2 years ago
13

What is 2/3 minus 1/5 equals? Steps I need to show.

Mathematics
2 answers:
notka56 [123]2 years ago
4 0
Firstly we need to find the common denominator:

2/3 - 1/5 =
= 10/15 - 3/15 =
= 7/15

We can't simplify it so that's the result :) I hope it will help you :)
OLEGan [10]2 years ago
3 0
It equals 7/15 
1. find the least common multiple of the 2 denominators(bottom numbers) 
for this problem: the lcm is 15(3 times 5)
2. the fractions will now be 10/15(2/3) and 3/15(1/59
3. subtract ONLY the numerators(upper numbers)
4. 10-3=7
5. your answer will be 7/15

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Answer:

d = 15.8 m

Step-by-step explanation:

Apply the Pythagorean Theorem to find the length of the diagonal.  The correct equation for this particular rectangle is

d = √(9² + 13²) = √250 = √25·√10 = 5√10

To the nearest tenth, this comes to d = 15.8 m

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2 years ago
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Yen paid $10.50 for 2.5 pounds of pretzels what price did she pay for each pound pretzels?​
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4.2$ for each pound of pretzels
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F(n)=4n-3 find the 15th term of the sequence defined by the explicit rule
pickupchik [31]

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57

Step-by-step explanation:

f(15)=4(15)-3

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7 0
2 years ago
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Find the common difference for the following sequence and fill in the missing terms. Show all calculations. 2, 13, 24, 35, __, _
Julli [10]

Step-by-step explanation:

Hey there!

Given sequences are; 2 , 13 , 24 , 35 , _ , _ .

Now,

Common difference (d) = 2nd term - 1st term. = 13-2 = 11

When we subtract 1st term from 2nd term we find 11 and when we subtract 2nd term from 3rd term we get 11. This means our common difference is 11.

Now, let's find the nrh term of the sequence.

nth term= a1 + (n-1)d ( <em>a1= 1st term, d= common</em> <em>difference</em>)

nth = 2+ (n-1) 11

= 2 + 11n - 11

= 11n - 9

Let's check if we have got nth term correct.

a1= 1*11 - 9 = 2

a2 = 2*11-9 = 13

a3 = 3*11 - 9 = 24

a4 = 4*11-9 = 35

So, we got our nth term.

Let's find remaining sequence.

a5= 5*11 - 9 = 46.

a6= 6*11 - 9 = 57.

Therefore, the remaining terms are : 46 and 57.

<em><u>Hope</u></em><em><u> it</u></em><em><u> helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>

7 0
2 years ago
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