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Valentin [98]
3 years ago
15

You calibrated a different pipet and determined its volume to be 25.40 mL. You then use it to determine the density of an unknow

n liquid. You use a fresh clean dry beaker with an initial mass of 48.7073 g. You pull the unknown liquid up to the mark in the pipet and transfer this to the beaker. The new mass of the beaker and liquid is 77.8760 g. What is the density of the unknown liquid
Physics
1 answer:
just olya [345]3 years ago
4 0

Answer:

1148.37401575 kg/m³

Explanation:

Volume of liquid in pipet

25.4 mL

Mass of liquid

77.8760-48.7073=29.1687\ g

Density is given by

\rho=\dfrac{m}{V}\\\Rightarrow \rho=\dfrac{29.1687}{25.4}\\\Rightarrow \rho=1.14837401575\ g/ml=1.14837401575\times 10^3=1148.37401575\ kg/m^3

The density of the unknown liquid is 1148.37401575 kg/m³

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6 0
4 years ago
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I am pushing in a large box with 200 N of force. Clint is pushing on the box with 200 N of force in the opposite direction. Why
andreev551 [17]

Answer:

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4 0
3 years ago
Find the electric force if charge A is 25 C and charge B is 40 C and they are placed .005m apart. Is this force attracting or re
swat32

Answer:

3.6 X 10^17 N; repelling or repulsion

Explanation:

According to coulombs law of electrostatic attraction which states that the force of attraction between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Mathematically,

F = kqAqB/d² where;

qA and qB are the charges

d is the distance between the charges.

k is the coulombs constant = 9×10^9Nm²/C²

Given qA = 25C, qB = 40C, d = 0.005m

Substituting the values in the formula we will have;

F = 9×10^9×25×40/0.005²

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Since the charges are both positive (like charges), they will repel.

According to the law of electrostatic attraction, like charges repel, unlike charges attracts.

8 0
3 years ago
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