Question

The average density of the Sun is on the order 103 kg/ m3 . (a) Estimate the diameter of the Sun. (b) Given that the Sun subtends at an angle of about half

Answer 1

Answer:

The diameter is  $\approx$$10^{11}m$ and $r_{sun} = 10^{9}$m

Explanation:

Given:

$m_{sun} = 10^{30} kg$

$\\p_{sun}= 10^{3}\frac{kg}{m^{3}}$

Required:

$r_{sun}$=?

d= ?

We know,

${v_{sun} = \frac{m_{sun}}{p_{sun}}$

       = $\frac{10^{30}}{10^{3}}$

       = $10^{27}m^{3}$

$v_{sun} = \frac{4}{3}\times\pi r^{3_{sun}}$

      $\approx$$r^{3}_{sun}$

$r_{sun} = 10^{9}$m

From the figure attached,

$sin\theta=\frac{r_{sun}}{d}}$

$d=\frac{r_{sun}}{sin\theta}}$

  =$\frac{10^{9}}{sin5}}$

   $\approx$$10^{11}m$

The diameter is  $\approx$$10^{11}m$ and $r_{sun} = 10^{9}$m