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2 years ago

Two dump trucks each have a mass of 1,500 kg. The distance of the dump truck

Physics

1 answer:

xxTIMURxx [149]2 years ago

4 0

Answer:

6.00 x 10⁻⁸N

Explanation:

Given parameters:

Mass of each dump trucks = 1500kg

Distance between them = 50m

Unknown:

New gravitational force between them = ?

Solution:

From Newton's law of universal gravitation,

F = $\frac{G m1 m2}{r^{2} }$

F is the gravitational force

G is the universal gravitation constant

m is the mass

r is the distance

F = $\frac{6.67 x 10^{-11} x 1500 x 1500}{50^{2} }$ = 6.00 x 10⁻⁸N

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A 200N force pushes forward on the 20kg truck. The truck pulls two crates connected together by ropes, as shown. The gravitation

devlian [24]

Force on left crate, right crate and truck we need to draw here

First we will write the equation for left crate

$T_{left} = m*a$

$T_{left} = 20*a$

Now similarly for right crate

$T_{right} - T_{left} = 20*a$

now for truck

$F - T_{right} = 20*a$

Now we know that F = 200 N

$200 - T_{right} = 20*a$

now add all three equation

$T_{left} + T_{right} - T_{left} + 200 - T{right} = 20a + 20 a + 20a$

$200 = 60 a$

$a = 10/3 m/s^2$

now we will find all tension using this value of acceleration

$T_{left} = 20 * \frac{10}{3} = \frac{200}{3} N$

$T_{right} - \frac{200}{3} = 20*\frac{10}{3}$

$T_{right} = \frac{400}{3} N$

6 0

3 years ago

A 3.00-kg object undergoes an acceleration given by a = (2.00 i + 5.00 j) m/s^2. Find (a) the resultant force acting on the obje

kobusy [5.1K]

Answer:

(a): The resultant force acting on the object are F= (5.99 i + 14.98 j).

(b): The magnitude of the resultant force are F= 16.4 N < 68.19º .

Explanation:

m= 3kg

a= 2 i + 5 j = 5 .38 < 68.19 º

F= m * a

F= 3* ( 5.38 < 68.19º )

F= 16.4 N < 68.19º

Fx= F * cos(68.19º)

Fx= 5.99

Fy= F* sin(68.19º)

Fy= 14.98

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3 years ago

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3 years ago

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Ilia_Sergeevich [38]

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3 years ago

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Veronika [31]

Answer:

Explanation:

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3 years ago