Question

A water rocket of mass 2.5 kg is launched vertically upwards from the surface of the Earth. It produces a steady thrust of 75 N. What is its acceleration?

Answer 1

Answer:

a = 30 [m/s²]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration. In this way, we have the following equation.

∑F = m*a

where:

m = mass = 2.5 [kg]

a = acceleration [m/s²]

F = force = 75 [N]

Now replacing:

$75=2.5*a\\a=75/2.5\\a=30[m/s^{2} ]$