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3 years ago

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Objects A and B have unlike charges. They are placed some distance apart and are exerting an electric force on each other. What

relationship does the inverse square proportionality in Coulomb's equation explain?. . a) distance and charge on either A or B. b) force and charge on both A and B together. c) force and distance. d) force and charge on either A or B

2 answers:

yawa3891 [41]3 years ago

5 0

Answer:

the answer is c for plato users

Explanation:

LuckyWell [14K]3 years ago

4 0

"Force and distance" are the ones among the following choices given in the question is the relationship that the inverse square proportionality in Coulomb's equation explain. The correct option among all the options that are given in the question is the third option or option "c". I hope the answer has helped you.

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Gravity causes all falling objects to accelerate at a rate of 98 m/s2.<br> O True<br> O False

aleksandrvk [35]

It’s true the acceleration of falling objects on earth due to gravity is 98ms2

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A cheetah can run at 30 m/s but only for about 12s. how far will it run in that time

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Read 2 more answers

7. A double-slit experiment uses coherent light of wavelength 633 nm with a slit separation of 0.100 mm and a screen placed 2.0

Illusion [34]

Answer:

The distance between first-order and second-order bright fringes is 12.66mm.

Explanation:

The physicist Thomas Young establishes through its double slit experiment a relationship between the interference (constructive or destructive) of a wave, the separation between the slits, the distance between the two slits to the screen and the wavelength.

$\Lambda x = L\frac{\lambda}{d}$ (1)

Where $\Lambda x$ is the distance between two adjacent maxima, L is the distance of the screen from the slits, $\lambda$ is the wavelength and d is the separation between the slits.

The values for this particular case are:

$L = 2.0m$

$\lambda = 633nm$

$d = 0.100mm$

Notice that is necessary to express L and $\lambda$ in units of milimeters.

$L = 2.0m \cdot \frac{1000mm}{1m}$ ⇒ $2000mm$

$\lambda = 633nm \cdot \frac{1mm}{1x10^{6}nm}$ ⇒ $6.33x10^{-4}mm$

Finally, equation 1 can be used:

$\Lambda x = (2000mm)\frac{(6.33x10^{-4}mm)}{(0.100mm)}$

$\Lambda x = 12.66mm$

Hence, the distance between first-order and second-order bright fringes is 12.66mm.

8 0

3 years ago

As a clump of interstellar gas contracts to become a main-sequence star, its changing position on the H-R diagram tells us _____

Stels [109]

Answer:

how its outward appearance is changing

Explanation:

H-R diagram is a fundamental tool used to classify stars. The position of stars on the H-R diagram is dependent on its luminosity and temperature.

The position of the star is represented by its outward appearance specially the color. The hottest and brightest the star, the more it lies between the red and blue color range.

The cooler stars lie on the right side of the H-R diagram while the hot stars lie on the left side of the H-R diagram.

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3 years ago

A bubble, located 0.200 m beneath the surface in a glass of beer, rises to the top. The air pressure at the top is 1.01 ???? 10

SIZIF [17.4K]

Answer:

the ratio of the bubble’s volume at the top to its volume at the bottom is 1.019

Explanation:

given information

h = 0.2 m

$P_{0}$ = 1.01 x $10^{5}$ Pa

$P_{1} V_{1} = P_{2} V_{2}$

$\frac{V_{2} }{V_{1}} = \frac{P_{1} }{P_{2}}$

$P_{1}$ = $P_{0}$ + ρgh, ρ = 1000 kg/ $m^{3}$

$P_{1}$ = 1.01 x $10^{5}$ Pa + (1000 x 9.8 x 0.2) = 1,0296 x $10^{5}$ Pa

$P_{2}$ = $P_{0}$ = $10^{5}$ Pa

thus,

$\frac{V_{2} }{V_{1}} = 1,0296 x [tex]10^{5}$ / $10^{5}$ = 1.019

8 0

3 years ago