Question

[MATH] I need some help with this, please! Brainliest for the 1#!!!​

Answer 1

a. AC is a diameter of the circle, so arc ABDC has measure 180º. Then

$135^\circ+(2t)^\circ+t^\circ=180^\circ$

$\implies135+3t=180$

$\implies3t=45$

$\implies\boxed{t=15}$

b. The angle formed by the two secants AE and BE has measure equal to half the difference between the intercepted arcs:

$m\angle AEB=\dfrac{m\widehat{AB}-m\widehat{CD}}2$

$\implies m\angle AEB=\dfrac{135^\circ-15^\circ}2=\boxed{120^\circ}$