In both problems, the sum of side lengths is the perimeter. Opposite sides of a parallelogram (or rectangle) are equal in length, so you can find the perimeter by doubling the sum of adjacent sides.
25. 2(x +(x +15)) = (x +45) +(x +40) +(x +25)
.. 4x +30 = 3x +110 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 80 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+30
.. 4x +30 = 4*80 +30 = 240
The perimeter of each is 240 units.
26. 2(x +(x +2)) = (x) +(x +6) +(x +4)
.. 4x +4 = 3x +10 . . . . . . . . . . . . . . . . . . . . . . simplify
.. x = 6 . . . . . . . . . . . . . . . . . . . . . . . . . . . . . . subtract 3x+4
.. 4x +4 = 4*6 +4 = 28
The perimeter of each is 28 units.
Answer:
trapazoid
Step-by-step explanation:
Answer:
9x-1
Step-by-step explanation:
The perimeter of the triangle is adding up all 3 sides.
(3x)+(x+6)+(5x-7)=P
9x-1 = perimeter
All I have done is combine like terms.
If there is a... x = something, replace x with the number.
Step-by-step explanation:
a. P(mites OR ticks) = P(mites) + P(ticks) − P(mites AND ticks)
P(mites OR ticks) = 0.80 + 0.30 − 0.20
P(mites OR ticks) = 0.90
b. P(no ticks | mites) = P(no ticks AND mites) / P(mites)
P(no ticks | mites) = (0.80 − 0.20) / 0.80
P(no ticks | mites) = 0.75
c. If two events are independent, then P(A and B) = P(A) × P(B).
P(mites AND ticks) = 0.20
P(mites) × P(ticks) = 0.80 × 0.30 = 0.24
They are not independent.
