Help is needed quickly.
1 answer:
This is for #1. Not sure about 2 and 3.
Example to help you with 2 and 3:
Solve the following pair of simultaneous linear equations:
Equation 1: 2x + 3y = 8
Equation 2: 3x + 2y = 7
Step 1: Multiply each equation by a suitable number so that the two equations have the same leading coefficient. An easy choice is to multiply Equation 1 by 3, the coefficient of x in Equation 2, and multiply Equation 2 by 2, the x coefficient in Equation 1:
3 * (Eqn 1) --->
3* (2x + 3y = 8)
---> 6x + 9y = 24
2 * (Eqn 2) --->
2 * (3x + 2y = 7)
---> 6x + 4y = 14 Both equations now have the same leading coefficient = 6
Step 2: Subtract the second equation from the first.
-(6x + 9y = 24
-(6x + 4y = 14)
5y = 10
Step 3: Solve this new equation for y.
y = 10/5 = 2
Step 4: Substitute y = 2 into either Equation 1 or Equation 2 above and solve for x. We'll use Equation 1.
2x + 3(2) = 8
2x + 6 = 8 Subtract 6 from both sides
2x = 2 Divide both sides by 2
x = 1
Solution: x = 1, y = 2 or (1,2).
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The time taken by the first and the second train is 1 hour 40 minutes and 1 hour 25 minutes. Then the time when the second train at Niles junction is 5:55 p.m.
<h3>What is speed?</h3>The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.
We know that the speed formula
A train leaves Thorn junction at 1:25 p.m. and arrives in Niles at 3:05 p.m. the train makes two stops along the route for a total of 15 minutes.
A second train leaves Thorn junction at 4:30 p.m. and heads to Niles.
This train does not make any stops.
Let the speed of both trains be equal.
Then the time taken by the first train will be
t₁ = 3:05 p.m. - 1:25 p.m.
t₁ = 1 hour 40 minutes
Then the time taken by the second train will be
t₂ = 1:40 - 00:15
t₂ = 1:25 = 1 hour 25 minutes
The time when the second train is at Niles junction will be
→ 4:30 p.m. + 1:25
→ 5:55 p.m.
More about the speed link is given below.
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