Answer:
absolute vlaue inequality: |x-3| > 9; solved: x<-6 and x>12
Step-by-step explanation:
I’m going to start this off by saying I learned all this right now by just searching up how to solve an absolute inequality equation and watching one video, so this might not be an accurate explanation. (I’m pretty sure the answer’s right though)
So an absolute value inequality must be written like this:
| x - a | *inequality* b
a is going to be the number that the inequality is centered around, in this case, 3. b will be how far you can deviate from that number, which in this case is 9.
Now, you will have this:
|x - 3| *inequality* 9
Now, to find the inequality, you need to understand the wording. If it says “more than” as it does here, then you would have the greater-than symbol (>). If you have “less than” then you’d have the less-than symbol (<). If the problem says “at least b away” then it would be greater-than-or-equal to (≥), and likewise, if it says “at most b away” then it would be less-than-or-equal-to (≤).
So now we're at:
|x - 3| > 9
To solve the equation, you just need to subtract 9(b) from 3(a) and add 9(a) to 3(b) to get -6 and 12. Since x must be more than 9 units away, you would get:
x<-6 and x>12
Hope this is helpful!
B. Angle 2 and angle seven are actually alternate exterior angles.
Answer:
Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is
.
Step-by-step explanation:
There are two kew parameters for a sphere: Center (
,
,
) and Radius (
). The radius is the midpoint of the line segment between endpoints. That is:
![C(x,y,z) = \left(\frac{-9+11}{2},\frac{-12+8}{2},\frac{-6+14}{2} \right)](https://tex.z-dn.net/?f=C%28x%2Cy%2Cz%29%20%3D%20%5Cleft%28%5Cfrac%7B-9%2B11%7D%7B2%7D%2C%5Cfrac%7B-12%2B8%7D%7B2%7D%2C%5Cfrac%7B-6%2B14%7D%7B2%7D%20%20%20%5Cright%29)
![C(x,y,z) = (1,-2,4)](https://tex.z-dn.net/?f=C%28x%2Cy%2Cz%29%20%3D%20%281%2C-2%2C4%29)
The radius can be found by halving the length of diameter, which can be determined by knowning location of endpoints and using Pythagorean Theorem:
![r = \frac{1}{2}\cdot \sqrt{(-9-11)^{2}+(-12-8)^{2}+(-6-14)^{2}}](https://tex.z-dn.net/?f=r%20%3D%20%5Cfrac%7B1%7D%7B2%7D%5Ccdot%20%5Csqrt%7B%28-9-11%29%5E%7B2%7D%2B%28-12-8%29%5E%7B2%7D%2B%28-6-14%29%5E%7B2%7D%7D)
![r = 10\sqrt{3}](https://tex.z-dn.net/?f=r%20%3D%2010%5Csqrt%7B3%7D)
The general formula of a sphere centered at (h, k, s) and with a radius r is:
![(x-h)^{2}+(y-k)^{2}+(z-s)^{2} = r^{2}](https://tex.z-dn.net/?f=%28x-h%29%5E%7B2%7D%2B%28y-k%29%5E%7B2%7D%2B%28z-s%29%5E%7B2%7D%20%3D%20r%5E%7B2%7D)
Hence, the equation of a sphere with one of its diameters with endpoints (-9, -12, -6) and (11, 8, 14) is
.
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![q(x) = {x}^{2} - 3x - 4](https://tex.z-dn.net/?f=q%28x%29%20%3D%20%20%7Bx%7D%5E%7B2%7D%20%20-%203x%20-%204)
![q(10) = ( {10})^{2} - (3 \times 10) - 4](https://tex.z-dn.net/?f=q%2810%29%20%3D%20%28%20%7B10%7D%29%5E%7B2%7D%20-%20%283%20%5Ctimes%2010%29%20-%204%20)
![q(10) = 100 - 30 - 4](https://tex.z-dn.net/?f=q%2810%29%20%3D%20100%20-%2030%20-%204)
![q(10) = 70 - 4](https://tex.z-dn.net/?f=q%2810%29%20%3D%2070%20-%204)
![q(10) = 66](https://tex.z-dn.net/?f=q%2810%29%20%3D%2066)
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Thus the correct answer is (( C )) .
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Answer: the answer is 2x-1