Answer: No, x+3 is not a factor of 2x^2-2x-12
========================================================
Explanation:
Let p(x) = 2x^2 - 2x - 12
If we divide p(x) over (x-k), then the remainder is p(k). I'm using the remainder theorem. A special case of the remainder theorem is that if p(k) = 0, then x-k is a factor of p(x).
Compare x+3 = x-(-3) to x-k to find that k = -3.
Plug x = -3 into the function
p(x) = 2x^2 - 2x - 12
p(-3) = 2(-3)^2 - 2(-3) - 12
p(-3) = 12
We don't get 0 as a result so x+3 is not a factor of p(x) = 2x^2 - 2x - 12
----------------------------------------
Let's see what happens when we factor p(x)
2x^2 - 2x - 12
2(x^2 - x - 6)
2(x - 3)(x + 2)
The factors here are 2, x-3 and x+2
Answer:
20
Step-by-step explanation:
15/75 %%:$%;%%_"$*^/%#
Price decrease = 14.3% of $52,000 = 0.143*$52,000 = $7,436
Price of next model = $52,000-$7,436 = $44,564
Answer:
1
Step-by-step explanation:
To find the answer, we divide the number of apples by the number of bags. This means we do 7 ÷ 4
7 ÷ 4 = 1.75
1.75 in fraction form is 1
Answer:
2.6 or 
Step-by-step explanation:
9d×10=240
÷10 ÷10
9d =24
÷9 ÷9
2.6 or
