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arsen [322]
3 years ago
5

Write each ratio in simpler form 36:90

Mathematics
1 answer:
Gnesinka [82]3 years ago
7 0
The answer to this in simpler form is 2/5
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-6x-14y=16 and -2x+7y=17 solve by elimination show the work
professor190 [17]

Answer:

(- 5, 1 )

Step-by-step explanation:

- 6x - 14y = 16 → (1)

- 2x + 7y = 17 → (2)

Multiplying (2) by - 3 and adding to (1) will eliminate the x- term

6x - 21y = - 51 → (3)

Add (1) and (3) term by term to eliminate x

0 - 35y = - 35

- 35y = - 35 ( divide both sides by - 35 )

y = 1

Substitute y = 1 into either of the 2 equations and solve for x

Substituting into (1)

- 6x - 14(1) = 16

- 6x - 14 = 16 ( add 14 to both sides )

- 6x = 30 ( divide both sides by - 6 )

x = - 5

solution is (- 5, 1 )

6 0
2 years ago
Find the difference 58.84 - 2.78​
VladimirAG [237]

Answer:

56.06

Step-by-step explanation:

 58.84

--  2.78

______

 56.06

I don't really know how else to explain this, but there ya go! Goodluck on your test or whatever you're doing! Stay safe ♥♥♥

8 0
3 years ago
Read 2 more answers
Solve the formula d = rt for t when d = 280 and r = 40
iragen [17]

Answer:

7

Step-by-step explanation:

280=40t/40

t=7

4 0
3 years ago
If A ⊂ B, then A ∩ B = ∅.<br>True or False
viktelen [127]
True I believe my friend.
4 0
3 years ago
If you need $8000 to travel to Europe after you graduate in 4 year. How much would your monthly deposits need to be if your acco
lina2011 [118]
\bf \qquad \qquad \textit{Future Value of an ordinary annuity}\\&#10;\left. \qquad \qquad \right.(\textit{payments at the end of the period})&#10;\\\\&#10;A=pymnt\left[ \cfrac{\left( 1+\frac{r}{n} \right)^{nt}-1}{\frac{r}{n}} \right]

\bf \qquad &#10;\begin{cases}&#10;A=&#10;\begin{array}{llll}&#10;\textit{accumulated amount}\\&#10;\end{array}\to &&#10;\begin{array}{llll}&#10;8000&#10;\end{array}\\&#10;pymnt=\textit{periodic payments}\\&#10;r=rate\to 5\%\to \frac{5}{100}\to &0.05\\&#10;n=&#10;\begin{array}{llll}&#10;\textit{times it compounds per year}\\&#10;\textit{monthly, thus twelve}&#10;\end{array}\to &12\\&#10;t=years\to &4&#10;\end{cases}

\bf 8000=pymnt\left[ \cfrac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]&#10;\\\\\\&#10;\cfrac{8000}{\left[ \frac{\left( 1+\frac{0.05}{12} \right)^{12\cdot 4}-1}{\frac{0.05}{12}} \right]}=pymnt\implies \cfrac{8000}{\frac{\left( \frac{241}{240} \right)^{48}-1}{\frac{1}{240}}}=pymnt&#10;\\\\\\&#10;\cfrac{8000}{53.0148852}\approx pymnt\implies 150.9010152318\approx pymnt
6 0
3 years ago
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