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Ugo [173]
3 years ago
13

Draw a figure that contains at least three angles and requires three letters to name each angle PLEASE HELP

Mathematics
2 answers:
Vladimir [108]3 years ago
7 0

You can draw a triangle or a quadrilateral since they have at least three angles. For the second part, any angle can be named with three letters. After naming each corner/angle of the figure, name an angle so that the actual angle letter is the middle letter, surrounded by the letters of the corners that is just next to it.

vichka [17]3 years ago
5 0

There are Infinite number of figure , that contains at least three angles and requires three letters to name each angle

1.Any of the Triangle, either Acute, Obtuse, Right, Scalene, Isosceles, or Equilateral.

2. Any of the Quadrilateral, Parallelogram,Rectangle, Square, Trapezoid, and Kite.

→Or In General

Any of the Polygon whether it is Regular or Irregular.

→Because, A polygon is defined as ,a simple closed figure made up of three or more line segment.

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3 points
stich3 [128]

Step-by-step explanation:

2x + 100 = 90

x = -5

Angle A = 45 - 5 = 40.

6 0
2 years ago
HELP ME SOMEBODY PLSS
OverLord2011 [107]

Answer:

-6/8

Step-by-step explanation:

The rate of change is the same as the slope (I don't know if you have learned that term yet), but basically its the change in y's over the change in x's. to find this out, all you have to do is count from the point on the graph that is the farthest right (in this case, (6,1)), up to the y coordinate of the point farthest to the left (-2, 7) which is 6, and then count the number of spaces between the x coordinates, which is 8. put the rise (up and down count) over the run (horizontal count) in a fraction form, which gives you 6/8, and then notice how the line is pointing towards the bottom RIGHT hand corner making the line negative, so you need to make the rate of change negative, giving you the final answer of -6/8.  

4 0
3 years ago
How to find x and the equation for it
vladimir2022 [97]

Answer:

Step-by-step explanation:To find the x intercept using the equation of the line, plug in 0 for the y variable and solve for x. You can also use the graph of the line to find the x intercept. Just look on the graph for the point where the line crosses the x-axis, which is the horizontal axis. That point is the x intercept.

8 0
3 years ago
Find a solution x = x(t) of the equation x′ + 2x = t2 + 4t + 7 in the form of a quadratic function of t, that is, of the form x(
Temka [501]
The particular quadratic solution to the ODE is found as follows:

x=at^2+bt+c
x'=2at+b

(2at+b)+2(at^2+bt+c)=t^2+4t+7
2at^2+(2a+2b)t+(b+2c)=t^2+4t+7

\begin{cases}2a=1\\2(a+b)=4\\b+2c=7\end{cases}\implies a=\dfrac12,b=\dfrac32,c=\dfrac{11}4

Note that there's also the fundamental solution to account for, which is obtained from the characteristic equation for the ODE:

x'+2x=0\implies r+2=0\implies r=-2

so that x_c=Ce^{-2t} is a characteristic solution to the ODE, and the general solution would be

x=Ce^{-2t}+\dfrac{t^2}2+\dfrac{3t}2+\dfrac{11}4
4 0
3 years ago
A rocket is launched at 85 ft./s from a launch pad that’s 28 feet above the ground. which equation can be used to determine the
3241004551 [841]

Answer:

h(t)=-16t^2+85t+28  is equation of height of rocket.

Option D is correct.

Step-by-step explanation:

Given: A rocket is launched with speed 85 ft/s from a height 28  feet.

Launching a rocket follows the path of parabola. The equation of rocket should be parabolic.

Parabolic equation of rocket is

Formula: h(t)=\dfrac{1}2gt^2+v_0t+h_0

g ⇒ acceleration due to gravity (-32 ft/s)

v ⇒ Initial velocity (v_0=85\ ft/s)

h ⇒ Initial height (h_0=28\ feet)

h(t) ⇒ function of height at any time t

Substitute the given values into formula

h(t)=\frac{1}{2}(-32)t^2+(85)t+28

h(t)=-16t^2+85t+28

D is correct.

6 0
3 years ago
Read 2 more answers
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