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Naddika [18.5K]
3 years ago
14

What is -3 1/2 divided by 4/9?

Mathematics
1 answer:
uysha [10]3 years ago
6 0

Answer:

Reduced Fraction :

\frac{ - 63}{8}

Decimal : -7.875

Step-by-step explanation:

1. Put both fractions in improper form

\frac{( - 3 \times 2)  -  1}{2}  =  \frac{ - 7}{2}

\frac{4}{9}  =  \frac{4}{9}

2. Multiply -7/2 by the reciprocal of 4/9 to get answer

<em>Concept</em><em> </em><em>:</em><em> </em>

<em>\frac{ \frac{1}{5} }{ \frac{1}{3} }  = ( \frac{1}{5}  \times  \frac{3}{1} )</em>

<em>\frac{ - 7}{2}   \times  \frac{9}{4} =  \frac{ - 63}{8}</em>

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Which equation represents a circle whose center is located at (- 6, 2) and whose radius is sqrt(10) units?
azamat

Answer:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

Step-by-step explanation:

The equation of a circle with center (a,b) and radius r, is

{(x - a)}^{2}  +  {(y - b)}^{2}  =  {r}^{2}

From the question, the center of the circle is located at (-6,2) and the radius is

r =  \sqrt{10}

We substitute the center and radius to get:

{(x -  - 6)}^{2}  +  {(y - 2)}^{2}  =  {( \sqrt{10} })^{2}

Simplify to obtain:

{(x  + 6)}^{2}  +  {(y - 2)}^{2}=10

7 0
2 years ago
Find the indicated probability or percentage for the sampling error. The distribution of weekly salaries at a large company is r
Flauer [41]

Answer:

The probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

Step-by-step explanation:

According to the Central Limit Theorem if we have a non-normal population with mean <em>μ</em> and standard deviation <em>σ</em> and appropriately huge random samples (<em>n</em> > 30) are selected from the population with replacement, then the distribution of the sample means will be approximately normally distributed.

Then, the mean of the distribution of sample means is given by,

\mu_{\bar x}=\mu

And the standard deviation of the distribution of sample means is given by,

\sigma_{\bar x}=\frac{\sigma}{\sqrt{n}}

The information provided is:

\mu=\$1000\\\sigma=\$370\\n=80

As <em>n</em> = 80 > 30, the central limit theorem can be used to approximate the sampling distribution of sample mean weekly salaries.

Let \bar X represent the sample mean weekly salaries.

The distribution of \bar X is: \bar X\sim N(\$1000,\ \$41.37)

Now we need to compute the probability of the sampling error made in estimating the mean weekly salary to be at most $75.

The sampling error is the the difference between the estimated value of the parameter and the actual value of the parameter, i.e. in this case the sampling error is, |\bar X-\mu|= 75.

Compute the probability as follows:

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                                     =P(-1.81

Thus, the probability that the sampling error made in estimating the mean weekly salary for all employees of the company by the mean of a random sample of weekly salaries of 80 employees will be at most $75 is 0.9297.

3 0
3 years ago
How can I work it out to find the product of 7-3,7
romanna [79]
You should do 7-3=4 then do what’s u have to do with the 7
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