In first diameter=8,In second diameter=2/3,
The window has a shape of a semi-circle (half of a circle).
We know the diameter d = 12 ft.
The area of a (complete) circle is given by the formula:
A = π × r²
The radius can be found by halving the diameter:
r = d ÷ 2
= 12 ÷ 2
= 6 ft
Therefore the area of the circle will be:
<span>A = π × r²
= 3.14 × 6</span>²
= <span>3.14 × 36
= 113.04 ft²
And the area of the semi-circle:
A = </span><span>113.04 </span>÷ 2
= 56.52 ft²
Hence, the area of the window will be 56.52 ft².
As you progress in math, it will become increasingly important that you know how to express exponentiation properly.
y = 2x3 – x2 – 4x + 5 should be written <span>y = 2^x3 – x^2 – 4^x + 5. The
" ^ " symbol denotes exponentiation.
I see you're apparently in middle school. Is that so? If so, are you taking calculus already? If so, nice!
Case 1: You do not yet know calculus and have not differentiated or found critical values. Sketch the function </span>y = 2x^3 – x^2 – 4^x + 5, including the y-intercept at (0,5). Can you identify the intervals on which the graph appears to be increasing and those on which it appears to be decreasing?
Case 2: You do know differentiation, critical values and the first derivative test. Differentiate y = 2x^3 – x^2 – 4^x + 5 and set the derivative = to 0:
dy/dx = 6x^2 - 2x - 4 = 0. Reduce this by dividing all terms by 2:
dy/dx = 3x^2 - x - 2 = 0 I used synthetic div. to determine that one root is x = 2/3. Try it yourself. This leaves the coefficients of the other factor, (3x+3); this other factor is x = 3/(-3) = -1. Again, you should check this.
Now we have 2 roots: -1 and 2/3
Draw a number line. Locate the origin (0,0). Plot the points (-1, 0) and (2/3, 0). This subdivides the number line into 3 subintervals:
(-infinity, -1), (-1, 2/3) and (2/3, infinity).
Choose a test number from each interval and subst. it for x in the derivative formula above. If the derivative comes out +, the function is increasing on that interval; if -, the function is decreasing.
Ask all the questions you want, if this explanation is not sufficiently clear.
Umm im not sure maby like 1+1 or sum
Given that a species of beetles grows 32% every year.
So growth rate is given by
r=32%= 0.32
Given that 100 beetles are released into a field.
So that means initial number of beetles P=100
Now we have to find about how many beetles will there be in 10 years.
To find that we need to setup growth formula which is given by
where A is number of beetles at any year n.
Plug the given values into above formula we get:
now plug n=10 years
Hence answer is approx 1606 beetles will be there after 20 years.
Now we have to find about how many beetles will there be in 20 years.
To find that we plug n=20 years
Hence answer is approx 25791 beetles will be there after 20 years.
Now we have to find time for 100000 beetles so plug A=100000
33.174666862=n
Hence answer is approx 33 years.
