Solve the simultaneous equations
x + 6y = 20
x + 3y = 14
x =
Y=
2 answers:
Answer:
x=8
Y=2
or
(x,y)=(8,2)
Step-by-step explanation:
x+6y=20
x+3y=14
solve the equation for x
x+6y=20
x=14-3y
substitute the given value of x into the equation
x+6y=20
14-3y+6y=20
14+3y=20
3y=20-14
3y=6
3y/3=6/3
y=2.
substitute the given value of y into the equation
x=14-3y
x=14-3×2
x=14-6
x=8.
the possible solution of the system is the <u>ordered</u><u> </u><u>pair</u> (x,y)
(x,y)=(8,2)
or
x=8
Y=2
Proof:
Check if the given <u>order</u><u>ed</u><u> </u><u>pair</u> is the solution of the system of equations
8+6×2=20
8+3×2=14
simply the equalities
20=20
14=14
since all of the equalities are true, the <u>ordere</u><u>d</u><u> </u><u>pair</u> is the solution of the system
(x,y)=(8,2)
Answer:
x = 8, y = 2
Step-by-step explanation:
Multiply the second equation by -2:
x + 6y = 20
-2x - 6y = -28
Add the equations and simplify:
-x = -8
x = 8
Plug x = 8 back into the first equation and solve for y:
8 + 6y = 20
6y = 12
y = 2
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