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navik [9.2K]
2 years ago
10

Solve the simultaneous equations x + 6y = 20 x + 3y = 14 x = Y=

Mathematics
2 answers:
antoniya [11.8K]2 years ago
7 0

Answer:

x=8

Y=2

or

(x,y)=(8,2)

Step-by-step explanation:

x+6y=20

x+3y=14

solve the equation for x

x+6y=20

x=14-3y

substitute the given value of x into the equation

x+6y=20

14-3y+6y=20

14+3y=20

3y=20-14

3y=6

3y/3=6/3

y=2.

substitute the given value of y into the equation

x=14-3y

x=14-3×2

x=14-6

x=8.

the possible solution of the system is the <u>ordered</u><u> </u><u>pair</u> (x,y)

(x,y)=(8,2)

or

x=8

Y=2

Proof:

Check if the given <u>order</u><u>ed</u><u> </u><u>pair</u> is the solution of the system of equations

8+6×2=20

8+3×2=14

simply the equalities

20=20

14=14

since all of the equalities are true, the <u>ordere</u><u>d</u><u> </u><u>pair</u> is the solution of the system

(x,y)=(8,2)

xxTIMURxx [149]2 years ago
6 0

Answer:

x = 8, y = 2

Step-by-step explanation:

Multiply the second equation by -2:

x + 6y = 20

-2x - 6y = -28

Add the equations and simplify:

-x = -8

x = 8

Plug x = 8 back into the first equation and solve for y:

8 + 6y = 20

6y = 12

y = 2

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