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docker41 [41]
3 years ago
10

What is the value of x in the equation 2.5x+10=x-0.5

Mathematics
1 answer:
lisabon 2012 [21]3 years ago
4 0

Answer:

x = 7

Step-by-step explanation:

Let's solve your equation step-by-step.

2.5x + 10 = x − 0.5

Step 1: Subtract x from both sides.

2.5x + 10 − x = x − 0.5 − x

1.5x + 10 = −0.5

Step 2: Subtract 10 from both sides.

1.5x +10 − 10= −0.5 − 10

1.5x = −10.5

Step 3: Divide both sides by 1.5.

1.5x/1.5 = -10.5/1.5

x = 7

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Divide 4 over 5 ÷ 1 over 10 = ___Divide 4 over 5 ÷ 1 over 10 = ____.
Alex777 [14]
4/5 divided by 1/10 is 8 the answer is 8
6 0
3 years ago
A number, y, is equal to the difference of a larger number and 3. The same number is one-third of the sum of the larger number a
mariarad [96]

Answer:

The two equations are

y = x - 3 and

3y = x + 9

Step-by-step explanation:

The options are not well stated. I'll answer the question without the options but however, my answer will be a reflection of one of the given options.

Given:

2 statements

Required

Write equivalent of both statements as equations

Let the large number be represented by x.

From the first statement (y, is equal to the difference of a larger number and 3)

Difference means minus (-); so, this statement is represented as follows to give us the first equation:

y = x - 3

From the second statement (The same number is one-third of the sum of the larger number and 9).

This is also represented as follows to give us the second equation

y = ⅓(x + 9)

Multiply both sides by 3

3 * y = 3 * ⅓(x + 9)

3y = x + 9

So, the two equations are

y = x - 3 and

3y = x + 9

4 0
3 years ago
Read 2 more answers
I have the first part but I don't know how to do the second part<br><br> h e l p
Debora [2.8K]

\bf \begin{array}{cll} \stackrel{ordinal}{position}&\stackrel{term}{value}\\ \cline{1-2} 1&12\\ 2&12+d\\ 3&12+d+d\\ 4&12+d+d+d\\ &12+3d \end{array}\qquad \implies ~\hfill \begin{array}{llll} \stackrel{\textit{4th term}}{12+3d}~~=~~\stackrel{\textit{4th value}}{3}\\\\ 3d=-9\implies d = \cfrac{-9}{3}\\\\ \stackrel{\textit{common difference}}{d = -3} \end{array}

well, we know the common difference is -3, to go from the 4th term to the 8th term, we need to add "d" 4 times or namely 3+4(-3), likewise to go from the 13th term to the 19th term we have to add "d" 6 times, or namely -24 + 6(-3).

\bf \stackrel{\textit{8th term}}{3+4(-3)}\implies 3-12\implies -9 \\\\\\ \stackrel{\textit{19th term}}{-24 + 6(-3)}\implies -24-18\implies -42

3 0
3 years ago
WILL GIVE BRAINLIEST!
Allushta [10]

Answer:

7 hot dogs, 4 wings

5 hotdogs, 5 wings

Step-by-step explanation:

4H + 7W 《56

H = 7, W = 4

4(7) + 7(4) = 56《56

H = 5 , W = 5

4(5) + 7(5) = 55《56

4 0
3 years ago
3(p-3) – 5p&gt;-3p- 6<br> How do u solve?
vampirchik [111]

Answer:

p>3

Step-by-step explanation:

<=> 3p - 9 - 5p > -3p - 6

<=> -2p + 3p > -6 + 9

<=> p > 3

5 0
3 years ago
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