A right triangle if i’m not mistaken
Your answer would like be 5 5/8
Answer:
no it is d
Step-by-step explanation:
put a value in for t and work it out for each problem i used 2
<h2>
Answer:</h2>
![2\vec{v}-6\vec{u}=(-52,48) \\ \\ ||2\vec{v}-6\vec{u}||=75.28}](https://tex.z-dn.net/?f=2%5Cvec%7Bv%7D-6%5Cvec%7Bu%7D%3D%28-52%2C48%29%20%5C%5C%20%5C%5C%20%7C%7C2%5Cvec%7Bv%7D-6%5Cvec%7Bu%7D%7C%7C%3D75.28%7D)
<h2>
Step-by-step explanation:</h2>
In this problem we have two vectors:
![\vec{u}=(5,-7) \ and \ \vec{v}=(-11,3)](https://tex.z-dn.net/?f=%5Cvec%7Bu%7D%3D%285%2C-7%29%20%5C%20and%20%5C%20%5Cvec%7Bv%7D%3D%28-11%2C3%29)
So we need to find two things:
![2\vec{v}-6\vec{u}](https://tex.z-dn.net/?f=2%5Cvec%7Bv%7D-6%5Cvec%7Bu%7D)
and:
![||2\vec{v}-6\vec{u}||](https://tex.z-dn.net/?f=%7C%7C2%5Cvec%7Bv%7D-6%5Cvec%7Bu%7D%7C%7C)
FIRST:
In this case we have the multiplication of vectors by scalars. A scalar is a simple number, so:
![2\vec{v}-6\vec{u} \\ \\ Replace \ \vec{v} \ and \ \vec{u} \ by \ the \ given \ vectors: \\ \\ 2(-11,3)-6(5,-7) \\ \\ Multiply \ each \ component \ by \ the \ corresponding \ scalar:\\ \\ (2\times (-11),2\times 3)+(-6\times 5,-6\times (-7)) \\ \\ (-22,6)+(-30,42) \\ \\ Sum \ of \ vectors: \\ \\ (-22-30,6+42) \\ \\ \therefore \boxed{(-52,48)}](https://tex.z-dn.net/?f=2%5Cvec%7Bv%7D-6%5Cvec%7Bu%7D%20%5C%5C%20%5C%5C%20Replace%20%5C%20%5Cvec%7Bv%7D%20%5C%20and%20%5C%20%5Cvec%7Bu%7D%20%5C%20by%20%5C%20the%20%5C%20given%20%5C%20vectors%3A%20%5C%5C%20%5C%5C%202%28-11%2C3%29-6%285%2C-7%29%20%5C%5C%20%5C%5C%20Multiply%20%5C%20each%20%5C%20component%20%5C%20by%20%5C%20the%20%5C%20corresponding%20%5C%20scalar%3A%5C%5C%20%5C%5C%20%282%5Ctimes%20%28-11%29%2C2%5Ctimes%203%29%2B%28-6%5Ctimes%205%2C-6%5Ctimes%20%28-7%29%29%20%5C%5C%20%5C%5C%20%28-22%2C6%29%2B%28-30%2C42%29%20%5C%5C%20%5C%5C%20Sum%20%5C%20of%20%5C%20vectors%3A%20%5C%5C%20%5C%5C%20%28-22-30%2C6%2B42%29%20%5C%5C%20%5C%5C%20%5Ctherefore%20%5Cboxed%7B%28-52%2C48%29%7D)
SECOND:
If we name:
![\vec{w}=2\vec{v}-6\vec{u}](https://tex.z-dn.net/?f=%5Cvec%7Bw%7D%3D2%5Cvec%7Bv%7D-6%5Cvec%7Bu%7D)
Then,
is the magnitude of the vector
. Therefore:
![||\vec{w}||=||2\vec{v}-6\vec{u}|| \\ \\ ||\vec{w}||=||(-52,48)|| \\ \\ ||\vec{w}||=\sqrt{(-58)^2+48^2} \\ \\ ||\vec{w}||=\sqrt{3364+2304} \\ \\ ||\vec{w}||=\sqrt{5668} \\ \\ \boxed{||\vec{w}||=75.28}](https://tex.z-dn.net/?f=%7C%7C%5Cvec%7Bw%7D%7C%7C%3D%7C%7C2%5Cvec%7Bv%7D-6%5Cvec%7Bu%7D%7C%7C%20%5C%5C%20%5C%5C%20%7C%7C%5Cvec%7Bw%7D%7C%7C%3D%7C%7C%28-52%2C48%29%7C%7C%20%5C%5C%20%5C%5C%20%7C%7C%5Cvec%7Bw%7D%7C%7C%3D%5Csqrt%7B%28-58%29%5E2%2B48%5E2%7D%20%5C%5C%20%5C%5C%20%7C%7C%5Cvec%7Bw%7D%7C%7C%3D%5Csqrt%7B3364%2B2304%7D%20%5C%5C%20%5C%5C%20%7C%7C%5Cvec%7Bw%7D%7C%7C%3D%5Csqrt%7B5668%7D%20%5C%5C%20%5C%5C%20%5Cboxed%7B%7C%7C%5Cvec%7Bw%7D%7C%7C%3D75.28%7D)
Answer:
A or C but i think its most likely A
Step-by-step explanation: