The answer is, 9/50
0.18 = 0.18/1
0.18/1 x 100/100 = 18/100
18/100 divided by 2/2 = 9/50
In conclusion the answer is 9/50.
Hopefully that helped! :)
Answer:
d> -3/16
Step-by-step explanation:
Answer:
A
Step-by-step explanation:
Combine like terms. The 5x is grouped to the 8x and the -7 isgrouped with the -55.
This means 5x + 8x = 13x and -7 - 55 = -62
The new expression is 13x - 62. We can't find the exact value of x because the expression wasn't set equal to anything.
By using the concept of uniform rectilinear motion, the distance surplus of the average race car is equal to 3 / 4 miles. (Right choice: A)
<h3>How many more distance does the average race car travels than the average consumer car?</h3>
In accordance with the statement, both the average consumer car and the average race car travel at constant speed (v), in miles per hour. The distance traveled by the vehicle (s), in miles, is equal to the product of the speed and time (t), in hours. The distance surplus (s'), in miles, done by the average race car is determined by the following expression:
s' = (v' - v) · t
Where:
- v' - Speed of the average race car, in miles per hour.
- v - Speed of the average consumer car, in miles per hour.
- t - Time, in hours.
Please notice that a hour equal 3600 seconds. If we know that v' = 210 mi / h, v = 120 mi / h and t = 30 / 3600 h, then the distance surplus of the average race car is:
s' = (210 - 120) · (30 / 3600)
s' = 3 / 4 mi
The distance surplus of the average race car is equal to 3 / 4 miles.
To learn more on uniform rectilinear motion: brainly.com/question/10153269
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