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Gnesinka [82]
4 years ago
11

While walking on ice, one should take small steps to avoid slipping. This because, smaller steps will ensure

Physics
1 answer:
o-na [289]4 years ago
4 0
That you won't slip while walking because you will have more balance and support
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What might happen if water molecules did not have a slight negative charge on one end and a slight positive charge on the other?
Katena32 [7]

Answer:

It would not be possible the cohesion among water molecules by the polar covalent bonding.

Well, to understand this in a better way, let's begin by explaining that water is special due to its properties, which makes this fluid useful for many purposes and for the existence of life.

In this sense, one of the main properties of water is cohesion (molecular cohesion), which is the attraction of molecules to others of the same type. So, water molecule (H_{2}O) has 2 hydrogen atoms attached to 1 oxygen atom and can  stick to itself through hydrogen bonds.

How is this possible?

By the polar covalent bonding, a process in which electrons are shared unequally between atoms, due to the unequal distribution of electrons between atoms of different elements. In other words: slightly positive and slightly negative charges appear in different parts of the molecule.  

Now, it can be said that a water molecule has a negative side (oxygen) and a positive side (hydrogen).  This is how the oxygen atom tends to monopolize more electrons and keeps them away from hydrogen. Thanks to this polarity, water molecules can stick together.

5 0
4 years ago
What do the arrows in this photograph represent?
Anna35 [415]

Answer:

<u>The answer would be D) gravity and air resistance.</u>

4 0
2 years ago
Which of the following is the best way to prepare for working in the health science environment
olga nikolaevna [1]

Answer:

Intern in a doctor's office.

Explanation:

3 0
3 years ago
Hawks and gannets soar above the ground and, when they spot prey, they fold their wings and essentially drop like a stone. They
BigorU [14]

Answer:

  v = 54.2 m / s

Explanation:

Let's use energy conservation for this problem.

Starting point Higher

         Em₀ = U = m g h

Final point. Lower

        Em_{f} = K = ½ m v²

        Em₀ = Em_{f}

        m g h = ½ m v²

         v² = 2gh

         v = √ 2gh

Let's calculate

         v = √ (2 9.8 150)

         v = 54.2 m / s

7 0
4 years ago
An unwary football player collides with a padded goalpost while running at a velocity of 5.70 m/s and comes to a full stop after
ollegr [7]
The relationship between the initial velocity, final velociy, distance, and deceleration can be expressed in the following equation.
          
                     2(a)(0.270 m) = 0² - (5.70 m/s)²

The value of a (which is the deceleration) is 0.06 m/s². Thus, the answer is that the deceleration value is approximately 0.06 m/s².
6 0
4 years ago
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