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faust18 [17]
3 years ago
11

At take off, a plane flies 100 km north before turning to fly 200 km east. How far is its destination from where the plane took

off?
Question 3 options:

300 km


224 km


200 km


173 km
Physics
1 answer:
Snowcat [4.5K]3 years ago
4 0
The answer is 300 km

To the destination
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Air in a 120 km/h wind strikes head on the face of abuilding 45m wide by 75m high and is brought to rest. if air has a mass of 1
AlekseyPX
From conservation of momentum, the ram force can be calculated similarly to rocket thrust:
 F = d(mv)/dt = vdm/dt.
 <span>In other words, the force needed to decelerate the wind equals the force that would be needed to produce it. 
</span><span> v = 120/3.6 = 33.33 m/s 
</span><span> dm/dt = v*area*density
</span> dm/dt = (33.33)*((45)*(75))*(1.3) 
 dm/dt = <span> 146235.375 </span><span>kg/s 
</span><span> F = v^2*area*density
</span> F = (33.33)^2*((45)*(75))*(1.3) = <span> <span>4874025 </span></span><span>N 
</span> This differs by a factor of 2 from Bernoulli's equation, which relates velocity and pressure difference in reference not to a head-on collision of the fluid with a surface but to a fluid moving tangentially to the surface. Also, a typical mass-based drag equation, like Bernoulli's equation, has a coefficient of 1/2; however, it refers to a body moving through a fluid, where the fluid encountered by the body is not stopped relative to the body (i.e., brought up to its speed) like is the case in this problem.
4 0
3 years ago
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In a football game, a receiver is standing still, having just caught a pass. Before he can move, a tackler, running at a velocit
Nataliya [291]

Answer:

A) mr = 100 kg

B) Fr = 210N

C) Ft = -199.5N

Explanation:

By conservation of the momentum:

mt*Vo = (mr + mt) * Vf  Solving for mr:

mr = mt*Vo / Vf - mt = 100 kg

The average force on the receiver:

mr *(Vf - 0) = Fr * Δt    Solving for Fr:

Fr = 210 N

The average force on the tackler:

mt * (Vf - Vo) = Ft * Δt    Solving for Ft:

Ft = -199.5 N

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3 years ago
Newton's First Law says that an object at rest will stay at rest, and an object in motion will stay in motion unless:
Verdich [7]

Answer: Acted on by equal forces in opposite direction

Explanation:

Newton's First Law says that every body continue in its state of rest or constant speed on a straight line unless being acted upon by an external force.

6 0
4 years ago
You and a friend each carry a 15 kg suitcase up two flights of stairs, walking at a constant speed. Take each suitcase to be the
AlekseyPX

Answer:

Both of you did the same work but you expended more power.

Explanation:              

<em>Work done</em> by an object is calculated by force applied multiplied by the distance.

  W=F*d

From the figure given below let us calculate force applied bith you and yopur friend.

Let us take the stairs in positive x direction,

Work done by you W₁ ,

The force applied Fₓ = F - mgsinθ =maₓ

here aₓ = 0, because both of you move with constant speed

F - mgsinθ = 0

F=  mgsinθ

The work done by you on the suitcase is

W = F L cos0°  ,    where L is he length of the staircase.

W = FL = mgsinθL ,  by substituting value of F

Work done by you is W₁ = mgLsinθ

Similarly work done by your friend is W₂ = mgLsinθ.

Because both of you carry suitcase of same weight and in staircase is in same angle the force applied is same .

Therefore <em>work done by both of you is same</em> . Both of you did equal work.

The power , is defined as amount of energy converted or transfered per second or rate at which work is done .

P =\frac{W}{t} =\frac{FL}{t}

Power spend by you P₁ = mgLsinθ/t

P₁ = 15*9.8*Lsinθ/30

P₁ = 4.9L sinθ  eqn 1

Power spend by your friend is P₂ = mgLsinθ/t

P₂ =15*9.8*Lsinθ/60

P₂ = 2.45Lsinθ    eqn 2

Dividing eqn 1 and eqn 2

P₁ = 2P₂

You have spend more power than your friend .

Hence Both of you did equal work but you spend more power.

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4 years ago
PLEAAASEE HELLPPPP?!?!?!
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Answer:

water evaporates into the atmosphere

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