Hawks and gannets soar above the ground and, when they spot prey, they fold their wings and essentially drop like a stone. They
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The magnitude of the electric field for 60 cm is 6.49 × 10^5 N/C
R(radius of the solid sphere)=(60cm)( 1m /100cm)=0.6m
Since the Gaussian sphere of radius r>R encloses all the charge of the sphere similar to the situation in part (c), we can use Equation (6) to find the magnitude of the electric field:
Substitute numerical values:
The spherical Gaussian surface is chosen so that it is concentric with the charge distribution.
As an example, consider a charged spherical shell S of negligible thickness, with a uniformly distributed charge Q and radius R. We can use Gauss's law to find the magnitude of the resultant electric field E at a distance r from the center of the charged shell. It is immediately apparent that for a spherical Gaussian surface of radius r < R the enclosed charge is zero: hence the net flux is zero and the magnitude of the electric field on the Gaussian surface is also 0 (by letting QA = 0 in Gauss's law, where QA is the charge enclosed by the Gaussian surface).
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1) The length of the lead is 1700 m
2) The frequency of the wave is 400 Hz
Explanation:
1)
The wave in this problem is a sound wave, which is produced by the vibrations of the particles of air. It is a type of longitudinal wave (which means that the vibrations occur back-and-forth along the direction of propagation of the wave).
The speed of a sound wave in air is approximately
v = 340 m/s
In this problem, the sound wave is heard after a time of
t = 5 s
after the shot. Therefore, the distance travelled by the wave in this time (and therefore, the length of the lead) is
2)
The frequency of a wave is the number of complete cycles made by the wave in one second.
For the wave in this problem, we are told that the wave has 2000 whole wavelengths in 5 seconds: this means that the wave completes 2000 cycles in 5 seconds. Therefore, we can find the frequency by setting up the following proportion:
where x is the number of cycles made in 1 second. Solving for x,
Therefore, the frequency of the wave is
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