This is an exponential growth/decay problem...
F=Ir^t, F=final value, I=initial value, r=rate, t=time, in this case:
F=I(1.03)^t and they just want to know when F=2I so
2=1.03^t take natural log of both sides...
ln2=t*ln1.03
t=ln2/(ln1.03)
t≈23.45
So it will take approximately 23.45 years for the population to double..
1990+23.45=2013.45
So during the year of 2013 the population will have double from its 1990 level.
Answer:
;fjk;rofkfk;;fkslgl;fkfls'rfi;,dfei;se;feieirjeiljlaejre
sfe;jflejflseleijflskfeselselehf
Step-by-step explanation:
ueufaepfsfjseuefkeou;oiwrrsdkuijksgukuisdjyfekefaehkf
R=12.13
A=pi×r²
A=pi×12.13²
A≈462.2442041
A≈462.2 (to the nearest tenth).
So the answer is A≈462.2.
46/100
31/100
2 20/100
4 32/100
Answer:
4x^2 +2x +16
Step-by-step explanation:
7x2 + 4x + 10) - (3x2 + 2x - 6)
Distribute the minus sign
7x2 + 4x + 10) - 3x2 - 2x + 6
Combine like terms
7x2 + 4x + 10)
- 3x2 - 2x + 6
-------------------------
4x^2 +2x +16
