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Dmitry [639]
4 years ago
15

Calculate each sum 2and3/8 + 5 and 1/4=

Mathematics
1 answer:
Ray Of Light [21]4 years ago
8 0

Answer:

Sum of 2 3/8 + 5 1/4 = 7 5/8

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Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
8=14n will give Brainly
Marina CMI [18]

Answer:

n = 4/7

Step-by-step explanation:

Step 1: Write equation

8 = 14n

Step 2: Divide both sides by 14

n = 8/14

Step 3: Simplify

n = 4/7

4 0
3 years ago
Read 2 more answers
I need help with numbers 1-4 please if someone could help me
laila [671]
You can use the slope formula or just calculate
\frac{rise}{run}
So for the first problem you run 3 units right and rise 5 units so
\frac{rise}{run}  =  \frac{5}{3}
2. Notice the y axis goes by 2 units.
\frac{ - 10}{4}  =  \frac{ - 5}{4}
3.
\frac{0}{12}  = 0
4.
\frac{2}{0}  = undefined
Please let me know if you have questions
3 0
4 years ago
brooke found the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form as follows​
Goryan [66]

Answer:

The equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

Step-by-step explanation:

Equation of line passing through the points (-7,25) and (-4,13) in slope-intercept form.

The general equation of slope-intercept form is: y=mx+b

First we need to find slope

The formula used for finding slope is: Slope=\frac{y_2-y_1}{x_2-x_1}

We are given: x_1=-7, y_1=25, x_2=-4, y_2=13

Putting values in formula and finding slope

Slope=\frac{y_2-y_1}{x_2-x_1}\\Slope=\frac{13-25}{-4-(-7)}\\Slope=\frac{13-25}{-4+7}\\Slope=\frac{-12}{3}\\Slope=-4

So, slope m= -4

Now finding y-intercept

Using slope m=-4 and point (-7,25) we can find y-intercept

y=mx+b\\25=-4(-7)+b\\25=28+b\\b=25-28\\b=-3

So, y-intercept b =-3

Now, the equation of required line having slope m=-4 and  y-intercept b=-3 is:

y=mx+b\\y=-4x-3

So, the equation of the line passing through the points (-7,25) and (-4,13) in slope-intercept form is \mathbf{y=-4x-3}

3 0
3 years ago
I need it ASAP, Questions are attached as a photo
ELEN [110]

Answer:

8- 26 cm

7- 85 cm^2

1-23 cm

5 0
2 years ago
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