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den301095 [7]
3 years ago
6

Find the first six terms of the sequence. a1 = 1, an = 4 • an-1

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer:

1,4,16,64,245,1024

Step-by-step explanation:

a1 =1

an = 4 * an-1

Let n = 2

a2 = 4*a1 = 4*1=4

Let n = 3

a3 = 4*a2 = 4*4 = 16

Let n = 4

a4 = 4*a3 = 4*16 = 64

Let n = 5

a5 = 4*a4 = 4*64 = 256

Let n = 6

a6 = 4*a5 = 4*256 = 1024

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Answer: 30ft

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2 years ago
I need how with plz
omeli [17]

Answer:

165 degrees

Step-by-step explanation:

According to the protractor, the angle stretches from 10 degrees to 175 degrees. Subtract 10 from 175 to get the total measurement, and you will get 165. The angle is 165 degrees.

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3 years ago
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Is 4/5 less than 5/6 or greater than
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Answer:4/5 is less than 5/6

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Suppose line segment AB has one endpoint at A(0, 0). What are the coordinates of B if (5, 3) is 1/3 of the way from A to B?
prisoha [69]

Answer:

B(x_2,y_2)= (20,12)

Step-by-step explanation:

Given

A = (0,0)

Ratio; m : n = 1 : 3

Point\ at\ 1 : 3 = (5,3)

Required

Coordinates of B

This question will be answered using line ratio formula;

(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n})

In this case:

(x,y) = (5,3)

(x_1,y_1) = (0,0)

m : n = 1 : 3

Solving for (x_2,y_2)

(x,y) = (\frac{mx_2 + nx_1}{m + n},\frac{my_2 + ny_1}{m + n}) becomes

(5,3) =  (\frac{1 * x_2 + 3 * 0}{1 + 3},\frac{1 * y_2 + 3 * 0}{1 + 3})

(5,3) =  (\frac{x_2 + 0}{4},\frac{y_2 + 0}{4})

(5,3) =  (\frac{x_2}{4},\frac{y_2}{4})

Comparing the right hand side to the left;

\frac{x_2}{4} = 5 -- (1)

\frac{y_2}{4} = 3 -- (2)

Solving (1)

x_2 = 5 * 4

x_2 = 20

Solving (2)

y_2 = 3 * 4

y_2 = 12

Hence;

B(x_2,y_2)= (20,12)

5 0
3 years ago
Patrick raced round a 440 metre circular track and stopped suddenly after 900 metres . How far was she from the starting point a
castortr0y [4]

Answer:

20 meters

Step-by-step explanation:

The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.

So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.

The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be 900-880=20 meters from the starting point.

8 0
3 years ago
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