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den301095 [7]
3 years ago
6

Find the first six terms of the sequence. a1 = 1, an = 4 • an-1

Mathematics
1 answer:
Nikolay [14]3 years ago
4 0

Answer:

1,4,16,64,245,1024

Step-by-step explanation:

a1 =1

an = 4 * an-1

Let n = 2

a2 = 4*a1 = 4*1=4

Let n = 3

a3 = 4*a2 = 4*4 = 16

Let n = 4

a4 = 4*a3 = 4*16 = 64

Let n = 5

a5 = 4*a4 = 4*64 = 256

Let n = 6

a6 = 4*a5 = 4*256 = 1024

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The answwe is undefined slope there is no slope 
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Which subset of real numbers does the square root of 3 belong to​
Tatiana [17]

Answer:

It is a Irrational Number.

Step-by-step explanation:

4 0
3 years ago
Which ordered pair is a solution to the equation y= 6x - 2?
Dmitry [639]

Answer:

  • (5, 28)

Step-by-step explanation:

  • y= 6x - 2

Verifying pairs:

(1,0)

  • 0 = 6*1 - 2
  • 0 = 4 - incorrect

(5, 28)

  • 28 = 6*5 - 2
  • 28 = 30 -2
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(6, 20)

  • 20 = 6*6 - 2
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(3, 19)

  • 19 = 6*3 - 2
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4 0
3 years ago
Right triangle XYZ has right angle Z. If the sin(X)=1213<br> , what is the cos(X)
AlekseyPX

Given:

Right triangle XYZ has right angle Z.

\sin(x)=\dfrac{12}{13}

To find:

The value of \cos x.

Solution:

We know that,

\sin^2(x)+\cos^2(x)=1

\cos^2(x)=1-\sin^2(x)

\cos(x)=\pm\sqrt{1-\sin^2x}

For a triangle, all trigonometric ratios are positive. So,

\cos(x)=\sqrt{1-\sin^2x}

It is given that \sin(x)=\dfrac{12}{13}. After substituting this value in the above equation, we get

\cos(x)=\sqrt{1-(\dfrac{12}{13})^2}

\cos(x)=\sqrt{1-\dfrac{144}{169}}

\cos(x)=\sqrt{\dfrac{169-144}{169}}

\cos(x)=\sqrt{\dfrac{25}{169}}

On further simplification, we get

\cos(x)=\dfrac{\sqrt{25}}{\sqrt{169}}

\cos(x)=\dfrac{5}{13}

Therefore, the required value is \cos(x)=\dfrac{5}{13}.

6 0
3 years ago
Two cars simultaneously left Points A and B and headed towards each other, and met after 2 hours and 45 minutes. The distance be
zheka24 [161]
<h2>Hello!</h2>

The answer is:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

<h2>Why?</h2>

To calculate the speed of the cars, we need to write two equations in order to create a relation between the two speeds and be able to isolate one in function of the other.

So, let be the first car speed "x" and the second car speed "y", writing the equations we have:

For the first car:

x_{FirstCar}=x_o+v*t

For the second car:

We know that the speed of the second car is the speed of the first car plus 14 mph, so:

x_{SecondCar}=x_o+(v+14mph)*t

Now, we already know that both cars met after 2 hours and 45 minutes, meaning that positions will be the same at that moment, and the distance between A and B is 264 miles,  so, we can calculate the relative speed between them:

If the cars are moving towards each other the relative speed will be:

RelativeSpeed=FirstCarSpeed-(-SecondCarspeed)\\\\RelativeSpeed=x-(-x-14mph)=2x+14mph

Then, since we know that they covered a combined distance which is equal to 264 miles of distance in 2 hours + 45 minutes, we  have:

2hours+45minutes=120minutes+45minutes=165minutes\\\\\frac{165minutes*1hour}{60minutes}=2.75hours

Writing the equation, we have:

264miles=(2x+14mph)*t\\\\264miles=(2x+14mph)*2.75hours\\\\2x+14mph=\frac{264miles}{2.75hours}\\\\2x=96mph-14mph\\\\x=\frac{82mph}{2}=41mph

We have that the speed of the first car is equal to 41 mph.

Now, for the second car we have that:

SecondCarSpeed=FirstCarSpeed+14mph\\\\SecondCarSpeed=41mph+14mph=55mph

Hence, we have that:

FirstCarSpeed=41mph\\SecondCarSpeed=55mph

Have a nice day!

4 0
3 years ago
Read 2 more answers
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