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MakcuM [25]
3 years ago
7

Please help thank you​

Mathematics
1 answer:
nikdorinn [45]3 years ago
6 0

Answer:

See explanation

Step-by-step explanation:

(x^2+9x+10)(x-2)= \\\\x^3-2x^2+9x^2-18x+10x-20= \\\\x^3+7x^2-8x-20

Jimmy is incorrect.

Using long division, you can find that the real answer.

First, subtract x^2(x-2) from the original expression, leaving you with 9x^2+2x-40.

Next, subtract 9x(x-2) from the expression, leaving you with 20x-40. Finally, subtract 20(x-2) from the expression, leaving you with a remainder of 0. This means that the real quotient is x^2+9x+20. Hope this helps!

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egoroff_w [7]

Answer:

it would be decreasing

Step-by-step explanation:

because it is a linear increasing function

for 1 it is going up from 1-6

and 2 it is a function because there isn't any multiples of the x values/ inputs that go to one y value/ output.

7 0
2 years ago
A quadratic equation function f(x)=ax^2 passes through (0,0) and (5,5). write an equation for this function
Alex
Equation: f(x)=(1/5)x^2 or f(x)=(0.2)x^2

Check:
f(0)=(1/5)(0)^2
f(0)=(1/5)(0)
f(0)=0✓
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4 years ago
(20pts) I need to know who is incorect and why
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Answer:

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Step-by-step explanation:

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6 0
3 years ago
How do I do this? Thank you!!
tatuchka [14]

Answer:

See explanation below

Step-by-step explanation:

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7 0
3 years ago
Read 2 more answers
The sum of three consecutive even integers is 36 . find the smallest of them​
bonufazy [111]

Answer:

10

Step-by-step explanation:

You can get the three consecutive integers by using <em>algebraic expressions.</em>

Let's solve.

Let x be the <u>smallest even integer</u>.

Let x+2 be the second even integer.

Let x+4 be the largest even integer.

  • x+x+2+x+4 = 36
  • 3x+6 = 36
  • 3x = 36-6
  • 3x = 30
  • x = \frac{30}{3}
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Therefore, 10 is the smallest even integer.

x+2 = 10+2 = 12

The second even integer is 12.

x+4 = 10+4 = 14

The largest even integer is 14.

Let's check by adding the three even integers.

10+12+14 = 36

36 = 36

<em>It's correct. </em>

7 0
3 years ago
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