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andrew11 [14]
3 years ago
8

Write a description of the three different possibilities that may occur when graphing a system of two linear equations.

Mathematics
1 answer:
Gelneren [198K]3 years ago
3 0
There could be an infinite number of solutions, one solution, or no solution at all.
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X- 12 = 5x2 in standard form
Rudik [331]

Answer:

It is: -5x^2 + x - 12 = 0

Step-by-step explanation:

4 0
3 years ago
Determine the x- and y- intercepts for the graph equation y = -8
FromTheMoon [43]

Answer:

b. No x-intercept y-intercept is (0, -8)

7 0
3 years ago
Read 2 more answers
A metal hollow bar whose cross section and dimension are shown below weighs 8x10^3 kg/m^3 and measure 2m in length ..determine t
devlian [24]
1) We calculate the volume of a metal bar (without the hole).

volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²

Volume=(0.935 m²)(2 m)=1.871 m³

2) we calculate the volume of the parallelepiped

Volume of a parallelepiped= area of the section  x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³

3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar -  volume of a parallelepiped

Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³

4) we calculate the mass of the metal bar

density=mass/ volume  ⇒ mass=density *volume

Data:
density=8.10³ kg/m³
volume=1.551 m³

mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg

answer: The mas of the metal bar is 12.408x10³ kg  or   12408 kg  


4 0
3 years ago
Find the missing dimension of the solid. Round your answer to the nearest 10th
Svetach [21]

Answer:

the answer is 9.9997 ft

Step-by-step explanation:

the equation to find the radius is

r = √(3v / πh)

5 0
3 years ago
An alloy is composed of nickel, zinc, and copper in a 7:2:9 ratio. How many kilograms of each metal is needed to make 3.8 kg of
Tamiku [17]
Ni : Zn: Cu = 7:2:9 =7x : 2x : 9x

7x+2x+9x = 3.8
18x=3.8
x=3.8/18=1.9/9≈0.21

Ni:   7x=7*0.21=1.47 ≈1.5 kg
Zn:  2x=2*0.21=0.42≈0.4 kg
Cu: 9x=9*0.21=1.89 ≈1.9 kg

Check 1.5+0.4+1.9 =3.8 True
6 0
3 years ago
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