Answer:
5.1
Step-by-step explanation:
Before we calculate the y value for the point Q that is located two thirds the distance from point P to point R, we need to get the distance of point p from point R using the formula for calculatingf the distance between two points
D = √(x2-x1)²+(y2-y1)²
Given P(−2, 7), and R(1, 0)
RP = √(1-(-2))²+(0-7)²
RP = √3²+(-7)²
RP = √9+49
RP =√58
To get the y value for point Q that is located two thirds the distance from point P to point R, this will give
PQ = y = 2/3 of √58
= 5.1
From the function y=x^2-4x+7
to complete the square we proceed as follows:
The vertex form is given by:
y=(x-h)^2+k
where (h,k) is the vertex:
thus from the function we shall have:
y=x^2-4x+7
c=(b/2a)²
c=(4/2)²=4
thus adding an subtracting 4 in the expression:
y=x^2-4x+4-4+7
y=(x-2)^2+3
thus the vertex will be:
(2,3)
The answer is:
<span>D. Minimum at (2, 3)</span>
Ten x plus four divided by seven
I guess it s 30 irdk
hope tis helps :D
